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crimeas [40]
2 years ago
10

A softball is hit into the outfield during a game. The initial velocity is 33.52 m/s, and the ball is hit at an angle of 27°. Ho

w far away should an opposing player stand to catch the ball? As
players are the same height. Show your work.
Physics
1 answer:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

weeeeeeeeeebeeeeeeeeeeeeeee

Explanation:

weeeeeeeeeee

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Superman is standing 393 m horizontally away from Lois Lane. A villain drops a rock from 4.00 m directly above Lois. If Superman
Sergio039 [100]

Answer:

-963.93 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 4=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4\times 2}{9.81}}\\\Rightarrow t=0.903\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow 393=0\times 0.0903+\frac{1}{2}\times a\times 0.903^2\\\Rightarrow a=\frac{393\times 2}{0.903^2}\\\Rightarrow a=963.93\ m/s^2

The acceleration of Superman would be -963.93 m/s² from Lois' perspective

6 0
3 years ago
What is the net force on a cart that is pulled to the right with 100 pounds of force and to the left with 30 pounds of force?
Arlecino [84]

Answer:

The answer to your question is: F = 70 pounds

Explanation:

To calculate the net force, only substract the left value to the right value.

                                F = F right  -  F left

                                F = 100 p - 30 p

                                F = 70 pounds

3 0
3 years ago
Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d
vodka [1.7K]
Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that F = k \frac{Q_1Q_2}{d^2} so if we double the charge on Q_1 and double the distance to (2d) we plug these into the equation to find

<span>F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}</span>

So we see the new force is exactly 1/2 of the old force so your answer should be \frac{1}{2}F if I can remember my physics correctly.

8 0
4 years ago
Read 2 more answers
A uniform metal rod of length 80cm and mass 3.2kg is supported horizontally by two vertical spring balance C and D. Balance C is
vagabundo [1.1K]

A uniform metal rod with of length 80cm and a mass of 3.2kg is supported horizontally by two vertical spring balances C and D. Balance C is 20cm from one end while D is 30cm from the other end would show the reading of 1.06 Kg and 2.13 kg respectively

<h3>What is gravity?</h3>

It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another, The gravity varies according to the mass and size of the body for example the force of gravity on the moon is the 1/6th times of the force of gravity on the earth.

As given in the problem, A uniform metal rod of the length of 80cm and mass of 3.2kg is supported horizontally by two vertical springs balance C and D. Balance C is 20cm from one end while D is 30cm from the other end

The weight of the rod acting downward is from the center of the rod at 40 cm

Let us suppose the reading on the spring balance C and D are P and Q respectively

By using the equilibrium for the vertical force

Fv=0

P + C = 3.2

By using the equilibrium for the moment around the left corner

20×P+ 50×Q= 40 ×3.2

By solving for both P and Q from the above two equations we would get

P =1.06 and Q = 2.13

Thus, the reading on the spring balance C and D would be 1.06 Kg and 2.13 kg respectively

Learn more about gravity from here

brainly.com/question/4014727

#SPJ1

5 0
1 year ago
In vertebrates, most of the fluid that ultimately exits the body as urine first enters the nephron tubules by the process of ___
Talja [164]
The water and solutes the first enters the nephron tubules undergo a process just before it exits the body as a urine. This process is called filtration. It operates when 20 percent of the solution volume is filtered in the renal corpuscle at a given time. It is reportedly stated that there are around 180 liters of this fluid being filtered by the kidney every day.
7 0
3 years ago
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