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2 years ago

13

Graph the following data tables on different graphs.

1 answer:

Anna [14]2 years ago

8 0

Answer:

Sjjsjsjsjsjsjsjwjwjw

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147.5 ml of ethyl alcohol (coefficient of volume expansion = 1120 x 10-6K-1) at a temperature of 273.1 K is measured into a 150.

marishachu [46]

Answer:

288.2 K

Explanation:

$\beta$ = Volumetric expansion coefficient = $1120\times 10^{-6}\ /K$

$T_i$ = Initial temperature = 273.1 K

$T_f$ = Final temperature

$v_0$ = Original volume = 150 mL

Change in volume is given by

$\Delta v=\beta v_0(T_f-T_i)\\\Rightarrow T_f=\frac{\Delta v}{\beta v_0}+T_i\\\Rightarrow T_f=\frac{150-147.5}{1120\times 10^{-6}\times 147.5}+273.1\\\Rightarrow T_f=288.2\ K$

The temperature of the ethyl alcohol should be 288.2 K to reach 150 mL

8 0

2 years ago

What is the wavelength of a wave that has a frequency of 841 Hz if the speed of the wave is 457 m/s?

Dvinal [7]

Answer:

<h3>The answer is 0.54 m</h3>

Explanation:

The wavelength of a wave can be found by using the formula

$\lambda = \frac{c}{f} \\$

where

c is the velocity

f is the frequency

So we have

$\lambda = \frac{457}{841} \\ = 0.543400713...$

We have the final answer as

<h3>0.54 m</h3>

Hope this helps you

6 0

2 years ago

Charging an object without touching it is called?

Airida [17]

<span>Charging by induction</span>

5 0

3 years ago

a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m

padilas [110]

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

Acceleration is the rate of change of velocity.
It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

Force is calculated by the equation, F = Mass × Acceleration
This is based on Newton's second law of motion.

Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 × 3.375 = 5062.5 N

4 0

2 years ago

Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame

VashaNatasha [74]

Answer:

a

$V = 5.30 *10^{-2} \ m^3$

b

$v_1 = 0.3127 \ m/s$

Explanation:

From the question we are told that

The number of identical drippers is n = 60

The diameter of each hole in each dripper is $d = 1.0 \ mm = 0.001 \ m$

The diameter of the main pipe is $d_m = 2.5 \ cm = 0.025 \ m$

The speed at which the water is flowing is $v = 3.00 \ cm/s = 0.03 \ m/s$

Generally the amount of water used in one hour = 3600 seconds is mathematically represented as

$V = A * v * 3600$

Here A is the area of the main pipe with value

$A = \pi * \frac{d^2}{4}$

=> $A = 3.142 * \frac{0.025^2}{4}$

=> $A = 0.0004909 \ m^2$

So

=> $V = 0.0004909 * 0.03 * 3600$

=> $V = 5.30 *10^{-2} \ m^3$

Generally the area of the drippers is mathematically represented as

$A_1= n * \pi \frac{d^2}{4}$

=> $A_1 = 60 * 3.142 * \frac{0.001 ^2}{4}$

=> $A_1 = 4.713 *10^{-5} \ m^2$

Generally from continuity equation we have that

$Av = A_1 v_1$

=> $0.0004909 * 0.03 = 4.713 *10^{-5} * v_1$

=> $v_1 = 0.3127 \ m/s$

3 0

2 years ago