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alexandr402 [8]
4 years ago
7

Can a observation be accurate but not precise?

Physics
1 answer:
laila [671]4 years ago
3 0
Sure 
"Mount Everest is 29,000 feet tall" or in scientific terms 2.9E4 
This statement/observation is accurate to 2 decimal places. It is precise only to (perhaps) the nearest thousand feet. 
More precise 
"Mount Everest is 29,029 feet tall"
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What can you infer about a wave with a short wavelength? Question 5 options: It has a low amplitude. It has a high amplitude. It
Galina-37 [17]

Option C is correct. It has a high frequency. Wavelength is inversly proportional to the frequency. For short-wavelength, the frequency will be high.

<h3>Describe the connection between wavelength & frequency?</h3>

Frequency and wavelength have an inverse connection with one another. As a result, the wave with a high frequency should have a short wavelength.

For short-wavelength, the frequency will be high.

Hence Option C is correct. It has a high frequency.

To learn more about the frequency refer  to the link;

brainly.com/question/14926605

4 0
3 years ago
Use the drop-down menus to answer the questions.
Softa [21]

Answer:

Use the drop-down menus to answer the questions.

Which fossil is the oldest?

✔ trilobite

Which fossil is the youngest?

✔ ammonite

Explanation:

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6 0
3 years ago
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A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upwa
Ksju [112]

The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.

The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.

At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.

At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.

Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2

=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2

=> v^2 = 11556/5

=> v = 48.07

<span>The velocity of the rocket when it impacts the ground is 48.07 m/s</span>

3 0
3 years ago
Plz Help ima fail science... <br> 25 points.
Neko [114]
Search up criterion and look at the examples and then read it and then make it in your own words
8 0
3 years ago
Calculate the frequency (v) in Hertz (Hz) of a wave that has a wavelength of 4.71 meters.
MissTica

Answer:

6.37 x 10⁷Hz

Explanation:

Given parameters:

Wavelength = 4.71m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

           V = F∧  

V is the velocity  = 3 x 10⁸m/s

F is the frequency

∧ is the wavelength

  3 x 10⁸  = F x 4.71

      F  = 63694267.52Hz = 6.37 x 10⁷Hz

           

6 0
3 years ago
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