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Sergio [31]
4 years ago
5

A cattleman has installed a new electric fence. The cows keep escaping because they are not deterred by the low power they exper

ience when touching the fence. There are two dials on his controls. Would you tell him to change the amperage or voltage? Support your answer with information from the lesson.
Physics
2 answers:
Bad White [126]4 years ago
7 0

I would increase the amperage because he amps dertance how much voltage is realsed.



Dafna11 [192]4 years ago
3 0
I would tell him to increase the amount of voltage so the cows would feel the electricity more than what they used to.this  is what i think 

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As you increase current, what happens to the strength of an electromagnet?
Maksim231197 [3]

As you increase current, the strength of an electromagnet intensifies.

3 0
3 years ago
Help ASAP thanks !!!
Ann [662]

Answer:

true

Explanation:

3 0
3 years ago
This person is fishing in a small, freshwater body of water. This body of water flows into a larger body of water called a river
ANEK [815]
Since the small body of water is connected to a larger body of water. so the small body of water will than be called a stream
6 0
4 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
yaroslaw [1]

Answer:

Energy =  1.5032*10^(-10) Joules

Explanation:

By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:

Energy = rest energy + kinetic energy.

            = m*c^2  + (γ - 1)*mc^2

Where γ depends on the velocity of the particle.

But if the proton is at rest, then the kinetic energy is zero, and γ = 1

Then the energy is just given by:

Energy = m*c^2

Where we know that:

mass of a proton = 1.67*10^(-27) kg

speed of light = c = 2.9979*10^(8) m/s

Replacing these in the energy equation, we get:

Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2

Energy = 1.5032*10^(-10) kg*m^2/s^2

Energy =  1.5032*10^(-10) J

5 0
3 years ago
A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1m/s^2 for 20s.
SSSSS [86.1K]

Answer:

A.) 1430 metres

B.) 80 seconds

Explanation:

Given that the train accelerates from rest at 1.1m/s^2 for 20s. The initial velocity U will be:

U = acceleration × time

U = 1.1 × 20 = 22 m/s

It then proceeds at constant speed for 1100 m

Then, time t will be

Time = distance/ velocity

Time = 1100/22

Time = 50 s

before slowing down at 2.2m/s^2 until it stops at the station.

Deceleration = velocity/time

2.2 = 22/t

t = 22/2.2

t = 10s

Using area under the graph, the distance between the two stations will be :

(1/2 × 22 × 20) + 1100 + (1/2 × 22 × 10)

220 + 1100 + 110

1430 m

The time taken between the two stations will be

20 + 50 + 10 = 80 seconds

6 0
3 years ago
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