How much will Paul save per year

Explain how you can use doubles when multiplying with 4 to find 4 X 8

liq [111]

If you want to evaluate it is 4, 4*8 But if u want to solve the function operation then it is 4 * 8. 32

3 0

3 years ago

Five times the difference of twice a number and seven is negative twenty-five. Find the number.

Sati [7]

The number is 1

Step-by-step explanation:

Let x be the required number

Then according to given statement

Five times the difference of twice a number and seven is negative twenty-five.

$5(2x-7) = -25$

Simplifying

$10x-35 = -25\\$

Adding 35 on both sides

$10x-35+35 = -25+35\\10x = 10$

Dividing both sides by 10

$\frac{10x}{10} = \frac{10}{10}\\x = 1$

Verification:

$5[2(1)-7] = -25\\5(2-7) = -25\\5(-5) = -25\\-25=-25$

Hence,

1 is the number

Keywords: Linear equation

Learn more about linear equation at:

#LearnwithBrainly

4 0

2 years ago

How long will each person take to run a total of 50 miles at the given rates?

forsale [732]

Problema Solution

Terrance and Jesse are training for a long-distance race. Terrance trains at a rate of 6 miles every half hour, and Jesse trains at a rate of 2 miles every 15 minutes.

How long will each person take to run a total of 50 miles at the given rates?

Answer provided by our tutors

d = 50 mi the distance
t1 = the time of Terrance
t2 = the time of Jesse
Terrance trains at a rate of 6 miles every half hour thus his rate is:
v1 = 6/0.5 = 12 mph
Jesse trains at a rate of 2 miles every 15 minutes thus his rate is:
v2 = 2/(15/60) = 8 mph
since speed = distance/time follows time = distance/speed:
t1 = d/v1
t1 = 50/12
t1 = 4 1/6 hr
t1 = 4 hr 10 min
t2 = d/v2
t2 = 50/8
t2 = 6 1/4 hr
t2 = 6 hr 15 min
Terrance will run 4 hours and 10 minutes.
Jesse will run 6 hours and 15 minutes.

6 0

2 years ago

"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

Let $p_1$ = proportion of drivers that were in compliance initially

$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

Now, P-value of the test statistics is given by;

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = 0.00043

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0

2 years ago

A television network is about to telecast a new television show. Before a show is launched, the network airs a pilot episode and

Basile [38]

Answer:

(E) 0.83

Step-by-step explanation:

We will solve it using conditional probability.

Let A be the event that a TV show is successful.

P(A) = 0.5

A' be event that the show is unsuccessful

P(A') =0.5

Let B be the event that the response was favorable

P(B) = 0.6

Let B' be the event that the response was unfavorable/

P(B') = 0.4

P(A∩B) = 0.5 and P(A∩B') = 0.3

We need to find new show will be successful if it receives a favorable response.

P(A/B) = $\frac{P(A∩B)}{P(B)}$

= 0.5/0.6

= 0.833

7 0

3 years ago

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