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Harlamova29_29 [7]
3 years ago
10

Two solutions, initially at 24.60°c, are mixed in a coffee cup calorimeter (ccal = 15.5 j/°c). when a 100.0 ml volume of 0.100 m

agno3 solution is mixed with a 100.0 ml sample of 0.200 m nacl solution, the temperature in the calorimeter rises to 25.30°c. determine the dh°rxn for the reaction as written below. assume that the density and heat capacity of the solutions is the same as that of water. nacl(aq) + agno3(aq) → agcl(s) + nano3(aq) dh°rxn = ?
Chemistry
1 answer:
Westkost [7]3 years ago
8 0

Hey there!:

moles of AgNO3 = 100 x 0.1 / 1000 = 0.01

moles of NaCl = 100 x 0.200 / 1000 = 0.02

volume of solution = 100 + 100 = 200 mL

mass of solution = 200 x 1 = 200 g

temperature rise = 25.30 - 24.60 = 0.70ºC

Therefore:

Q = m* Cp* ΔT + Cp* ΔT =

200* 4.184 * 0.70 + 15.5 * 0.70  =

Q = 596.61 J

Given the reaction:

Q = 596.61 J

NaCl(aq) + AgNO3(aq)--------> AgCl(s) + NaNO3(aq)

1 mole NaCl ------ 1 mole AgNO3 ------ 1 mole AgCl

0.02 moles NaCl ----- 0.01 moles AgNO3

So:

ΔH =  - Q / T

ΔH =  - 596.61 * 10⁻³ / 0.01

ΔH  = - 59.66 kJ


Hope that helps!



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Explanation:

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waist\ to\  height\  ratio = \frac{circumference\ of\ the\ waist}{height\ of\ the\ person}

circumference of waist =height\  of\  person \times waist\ to\ height ratio

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we know that circumference is given as = 2\pi r\ or\  \pi D= 37.21

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The picture below shows the mechanism

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