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Aleks [24]
3 years ago
8

The compound FeCI3 is made of ?

Chemistry
2 answers:
Natasha2012 [34]3 years ago
8 0

Hello! Your answer is C, one atom of iron and three atoms of chlorine.

In this case, there is some ambiguity with "Cl". It could be C + I, or Cl. (One being carbon + iodine and the other Chlorine). However, we can see that the only choice that mentions iodine states two atoms, which is incorrect, as if it was iodine, the 3 indicates that there would be three atoms.

Therefore, Cl must be chlorine. If you look at choice C, there are three atoms of chlorine, as indicated by the 3 at the end of the Cl. There is also one molecule of Fe, as there is no number at the end of it so there has to be only one.

B is not correct, as carbon would be only "C". A is not correct as a molecule is a collection of atoms bonded together, therefore, this compound could be named a molecule, but there are not multiple molecules inside this compound.

Hope this helps!

Pepsi [2]3 years ago
3 0

Answer:

C(one atom of iron and three atoms of chlorine

Explanation:

one atom of iron = Fe

three atoms of chlorine  = Cl₃

Fe²⁺ +  3Cl⁻ → FeCl₃

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How many atoms are there in 7.80 moles of germanium
Orlov [11]
<h3>Answer:</h3>

4.70 × 10²⁴ atoms Ge

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.80 mol Ge

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

\displaystyle 7.80 \ mol \ Ge(\frac{6.022 \cdot 10^{23} \ atoms \ Ge}{1 \ mol \ Ge} ) = 4.69716 × 10²⁴ atoms Ge

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Ge ≈ 4.70 × 10²⁴ atoms Ge

8 0
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Which of these elements is this group?
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Group 2 elements include the following: Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), barium (Ba), and radium (Ra). Based on the descriptive information in this question, the element being described is a GROUP 2 element. Based on the elements in the option, only STRONTIUM (Sr) is a group 2 element.

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guapka [62]
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3 years ago
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