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3 years ago

Which of the following values is equal to 1 micrometer?

Chemistry

2 answers:

viktelen [127]3 years ago

7 0

Answer : Option A) 0.000001 meter

Explanation : The value which will be equal to 1 micrometer will be 0.000001 meter.

As the conversion factor for 1 μm = $1 X 10^{-6}$ m

So while converting micrometer to meter will be by converting micrometer to meter $1 X 10^{-6}$ m in decimal it will be 0.000001 meter.

Crazy boy [7]3 years ago

6 0

1 micrometer is equal to 10⁻⁶m so the correct answer is A.) 0.000001 meter

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2 grams is the answer

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4 years ago

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You are given a protein solution with a concentration of 0.15 mg/ml.

Thepotemich [5.8K]

Answer:

We need 2.933 L of 0.15 mg /mL of protein solution.

Explanation:

Concentration of given solution $C_1 = 0.15 mg/mL$

1 mg = 0.001 g , 1 mL = 0.001 L

$C_1=\frac{0.15\times 0.001 mg}{1\times 0.001 L}=0.15 g/L$

Molecular weight of protein = 22,000 Da =22,000 g/mol

Initial concentration in moles/liter:

$C_1=\frac{0.15 g/L}{22,000 g/mol}=6.8182\times 10^{-6} mol/L$

Initial concentration in micromoles/mL :

1 L = 1000 mL

$C_1=6.8182\times 10^{-6} mol/L=\frac{6.8182\times 10^{-6}\times 10^6 \mu mol}{1000 mL}=6.8182\times 10^{-3} \mu mole/ mL$

Initial concentration in micromoles/microLiter :

1 L = 1000,000 μL

$C_1=6.8182\times 10^{-6} mol/L=\frac{6.8182\times 10^{-6}\times 10^6 \mu mol}{1000000 \mu L}=6.8182\times 10^{-6}\mu mol/\mu L$

Moles of protein required = 20 μmoles

n(Moles)=C(concentration) × V(Volume of solution)

$20 \mu mol=6.8182\times 10^{-6}\mu mol/\mu L\times V$

$V =\frac{20 \mu mol}{6.8182\times 10^{-6}\mu mol/\mu L}$

$V=2.933\times 10^6 \mu L = 2.933 L$

We need 2.933 L of 0.15 mg /mL of protein solution.

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3 years ago

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Isotopes have same atomic number but different atomic mass number.
Hence option B is correct.

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4 years ago

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Answer:

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3 years ago

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If a solution containing 117.63 g of silver chlorate is allowed to react completely with a solution containing 10.23 g of lithiu

GuDViN [60]

Answer:

18.8 g

Explanation:

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3 years ago