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4 years ago

How many mg of O2 will react with the TNT?

1 answer:

6 0

TNT has the molecular formula: C7H5N3O6. And hence, when reacted in oxygen gas, you get what is known as combustion reaction. the reaction is: C7H5N3O6+O2→CO2+N2+H2O

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Two of the types of infrared light, IR-B and IR-A, are both components of sunlight. Their wavelengths range from 1400 to 3000 nm

Simora [160]

To compare the energy of microwaves, IR-B, and IR-A, we need to compare how long the wavelengths are for each wave. Through the intervals given, we can determine that we in order from greatest to least energy, the order is IR-A, IR-B, microwaves.

3 0

3 years ago

Adding powdered limestone (calcium carbonate) to a lake affected by acid rain can decrease the availability of phosphate ion, an

Sauron [17]

Answer:

The reaction is:

H⁺

CaCO₃ ⇄ Ca²⁺ + CO₃ ⇄ HCO₃

The standard free energy change is ΔG = ΔH - TΔS

Explanation:

Limestone is a mineral familiar with calcium carbonate, and being very common, the acid present in acid rain dissolves it reacting with carbonate, since the acids present in acid rain are characterized by being highly soluble in water and are also strong acids. The reaction is as follows:

H⁺

CaCO₃ ⇄ Ca²⁺ + CO₃ ⇄ HCO₃

The spontaneity of the reaction is equal to:

ΔG = ΔH - TΔS

The sign of the standard free energy changes from positive to negative.

4 0

4 years ago

A 0.568-g sample of fertilizer contained nitrogen as ammonium sulfate, . It was analyzed for nitrogen by heating with sodium hyd

Mariulka [41]

Answer:

6.69%

Explanation:

Given that:

Mass of the fertilizer = 0.568 g

The mass of HCl used in titration (45.2 mL of 0.192 M)

= $0.192*\frac{45.2}{1000}* \frac{36.5}{1 \ mole}$

= 0.313 g HCl

The amount of NaOH used for the titration of excess HCl (42.4 mL of 0.133M)

= $\frac{44.3 \ mL * 1.0 \ L}{1000 \ mL} *0.133 \ mole/L$

= 0.0058919 mole of NaOH

From the neutralization reaction; number of moles of HCl is equal with the number of moles of NaOH is needed to complete the neutralization process

Thus; amount of HCl neutralized by 0.0058919 mole of NaOH = 0.0058919 × 36.5 g

= 0.2151 g HCl

From above ; the total amount of HCl used = 0.313 g

The total amount that is used for complete neutralization = 0.2151 g

∴ The amount of HCl reacted with NH₃ = (0.313 - 0.2151)g

= 0.0979 g

We all know that 1 mole of NH₃ = 17.0 g , which requires 1 mole of HCl = 36.5 g

Now; the amount of HCl neutralized by 0.0979 HCl = $\frac{17}{36.5}*0.0979$

= 0.0456 g

Therefore, the mass of nitrogen present in the fertilizer is:

= $0.0456 \ g \ NH_3 * \frac{1 \ mol \ NH_3 }{17.0 \ mol \ of \ NH_3} * \frac{1 \mol \ (NH_4)_2SO_4}{2 \ mol \ NH_3 } * \frac{2 \ mol \ N }{1 \mol \ (NH_4)_2SO_4}* \frac{14.0 g }{1 \ mol \ N}$

= 0.038 g

∴ Mass percentage of Nitrogen in the fertilizer = $\frac{0.038 \ g}{0.568 \ g} * 100$ %

= 6.69%

8 0

4 years ago

Read 2 more answers

I have 1.8066 x 1024 atoms of Calcium, how many grams of calcium do I have?

Vera_Pavlovna [14]

Answer: 1849.9584

Explanation:

8 0

3 years ago

If i initially have a gas with a pressure of 84 kpa and a temperature of 350 c and i heat it an additional 230 degrees, what wil

Ganezh [65]

Answer:

67.824

Explanation: You want to use the combined gas law equation (P1*V1)/(n1*T1)=(P2*V2)/(n2*T2). So first cross out what remains constant, so volume(V) and I assume moles (since it was not mentioned as a change). Then you can solve algebraically for the answer!

Hope this helped!

5 0

3 years ago