Answer:
The answer to your question is SrCrO₄ + H₂O
Explanation:
Data
H₂CrO₄ + Sr(OH)₂ ⇒
We can notice that this is a Redox reaction or neutralization reaction because the reactants are an acid (H₂CrO₄) and a base (Sr(OH)₂). These reactions are also called double displacement reactions.
In these kind of reactions the products are always a binary or ternary salt and water.
Then, for this reaction,
H₂CrO₄ + Sr(OH)₂ ⇒ SrCrO₄ + H₂O
Answer:
The molecular weight of the unknown gas is 16.1 g/mol.
The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.
The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.
Now, we will consider each reaction individually to decode whether or not a precipitate is possible.
- In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
- In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
- In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.
Learn more: brainly.com/question/11969651
