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2 years ago

Which American Indian group formed an alliance with the British as the French and Indian War began?

Mathematics

2 answers:

goblinko [34]2 years ago

7 0

I think the correct answer is A

blondinia [14]2 years ago

6 0

Answer:

Option: A is the correct answer.

A. The Huron

Step-by-step explanation:

The Wyandot people or Wendat, also called the Huron Nation and Huron people, are an Iroquoian-speaking peoples of North America who emerged as a tribe around the north shore of Lake Ontario.

During the Northwest Indian War, the Huron fought alongside British allies against the United States.

Hence, the correct answer is:

A. The Huron

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Last Saturday, Niki went on a bike ride from her house to the park. The total distance she travelled on her bike was 3 1/5 miles

Mnenie [13.5K]

Answer:

D. $\frac{16}{5}$

Step-by-step explanation:

$3\frac{1}{5}$

To rewrite a mixed number as an improper fraction, first, multiply the whole number by the denominator.

$3*5=15$

Then, add this number to the numerator.

$15+1=16$

This number is now the numerator of the fraction. The denominator stays the same.

$\frac{16}{5}$

I hope this helps!

5 0

2 years ago

Read 2 more answers

What is the tangent of 0?

algol [13]

Answer: Tis 0

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The owner of the Rancho Grande has 3,044 yd of fencing with which to enclose a rectangular piece of grazing land situated along

inysia [295]

Answer:

Step-by-step explanation:

Area of the rectangular piece A = xy

x is the length

y is the width

Perimeter =2x+2y

Given

Perimeter = 3044yds

3044 = 2x+2y

1522 = x+y

x = 1522-y

Substitute into the formula for area

A = xy

A = (1522-y)y

A = 1522y-y²

To maximize the area, dA/dy must be zero

dA/dy = 1522-2y

0 = 1522-2y

2y = 1522

y = 1522/2

y = 761

Since x+y = 1522

X+761 = 1522

X = 761

Dimension is 761yd by 761yd

Area = 761×761 = 579121yd²

7 0

2 years ago

As part of the Pew Internet and American Life Project, researchers conducted two surveys in late 2009. The first survey asked a

REY [17]

Answer:

The 95% confidence interval for the difference between the proportion of all U.S. teens and adults who use social networking sites is (0.223, 0.297). This means that we are 95% sure that the true difference of the proportion is in this interval, between 0.223 and 0.297.

Step-by-step explanation:

Before building the confidence interval we need to understand the central limit theorem and the subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample of 800 teens. 73% said that they use social networking sites.

This means that:

$p_T = 0.73, s_T = \sqrt{\frac{0.73*0.27}{800}} = 0.0157$

Sample of 2253 adults. 47% said that they use social networking sites.

This means that:

$p_A = 0.47,s_A = \sqrt{\frac{0.47*0.53}{2253}} = 0.0105$

Distribution of the difference:

$p = p_T - p_A = 0.73 - 0.47 = 0.26$

$s = \sqrt{s_T^2+s_A^2} = \sqrt{0.0157^2+0.0105^2} = 0.019$

Confidence interval:

Is given by:

$p \pm zs$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Lower bound:

$p - 1.96s = 0.26 - 1.96*0.019 = 0.223$

Upper bound:

$p + 1.96s = 0.26 + 1.96*0.019 = 0.297$

3 0

2 years ago

Polygon ABCDE has the vertices A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6). Polygon MNOPQ has the vertices M(-2, 8), N(-4

Leto [7]

A transformation that can be performed on polygon ABCDE is a reflection over the y-axis.
The image of a polygon by a reflection its mirror image. The reflected image has the same size as the original.
It means that polygon ABCDE is congruent to polygon MNPQ.

9 0

2 years ago