Please help!!!!! Fast please

Some triangles can have more than one obtuse angle. True or false?

Reptile [31]

False. A triangle can't have more than one obtuse angle.

7 0

3 years ago

Are these fractions equivalent or nonequivalent? xy/4y x/4

Nina [5.8K]

Answer:

They are equivalent

Step-by-step explanation:

x/4 multiplied by y/y equals to xy/4y. Therefore, they are equivalent

8 0

2 years ago

(+1)+(+4) =

marishachu [46]

Answer:

5

8

3

15

8

16

6

10

3

9

14

6

9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The fox population in a certain region has an annual growth rate of 4 percent per year. It is estimated that

Minchanka [31]

Answer:

(a) P(t) = 12100*(1.04^t)

(b) in 2008, estimate of population is 16560 (to the nearest integer)

Step-by-step explanation:

Population in 2000, P(0) = 12100

Growth rate = 4% each year

(a) function model for the t year after 2000 (exponential model)

P(t) = 12100*(1.04^t)

(b) for 2008,

P(2008-2000)

= P(8)

= 12100*(1.04^8)

= 12100 * 1.368569

= 16559.7

= 16560 (nearest integer)

7 0

2 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago