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Vedmedyk [2.9K]
3 years ago
11

What is the first step in solving the quadratic equation -5x2+8=133?

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

b. The first step in the equation solving is subtracting 8 from both sides of the equation.

Step-by-step explanation:

Here, the given quadratic equation is : -5x^2 + 8  = 133

Let us try and solve this given equation.

-5x^2 + 8  = 133 \\\implies -5x^2 + 8  - 8 = 133 -8\\\implies  -5x^2  =  125\\\implies  x^2  =\frac{125}{-5}  = -25\\\implies x^2  = -25 = (5i)^2

So, x  = ± 5i

Hence, as we can see here, the first step in the equation solving is subtracting 8 from both sides of the equation.

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Use the periodic compound interest formula to solve. Suppose that $12000 is invested at 3.6% compounded quarterly. Find the tota
AlekseyPX

Answer:

$ 17172.28

Step-by-step explanation:

Each period is 1/4 year ...in ten years there are 40 periods

Interest in decimal is .036      .....   per period this is  .036/4 = .009

The FV = PV (1+i)^n        FV = Future value  PV = present value  

          FV = 12 000 ( 1 + .009)^40 =17172.28

7 0
2 years ago
Correct answers only please!
blagie [28]

Answer: $86.25

Step-by-step explanation:

For this problem, we are given p, r, t.

p=70 (starting amount)

r=0.11 (11%)

t=2 (years)

We can plug this into the equation B=p(1+r)^t

B=70(1+0.11)^2

B=86.247

Sam would have $86.25

6 0
3 years ago
Read 2 more answers
Can someone like an ace or very good at math help me
eimsori [14]
Supplementary angles , when added, = 180
complimentary angles, when added, = 90

< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary

< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143

< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26

< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97

cant read all of the last one.....but if they are complimentary, and 
< U = 41, then the other angle is : (90 - 41) = 49


4 0
4 years ago
+++++
Strike441 [17]

Step-by-step explanation:

++++5

+++++++_2

1=false

true

false

false

4 0
2 years ago
Read 2 more answers
A line through the origin and (10,4) is showin in the standard (x,y) coordinate plane below. The acute angle between the line an
Snowcat [4.5K]

Answer:

\cos\theta=\frac{10}{\sqrt{116}}

Step-by-step explanation:

To solve this, we can imagine a line drawn directly down from the point (10,4) to the x-axis. This would make a right triangle with length 10 and height 4.

\cos\theta is equal to the length of adjacent leg to the angle divided by the length of the hypotenuse of the triangle. From the picture, we can see the adjacent leg is 10.

We can use Pythagorean's Theorem to find the hypotenuse (let c represent the length of the hypotenuse):

10^2+4^2=c^2

100+16=c^2

116=c^2

c=\sqrt{116}

Thus, we know the adjacent is 10, and the hypotenuse is \sqrt{116}. This means \cos\theta=\frac{10}{\sqrt{116}}.

Hope this helps!

5 0
3 years ago
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