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Evgen [1.6K]
3 years ago
5

A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/p cycles/s, what is the spring const

ant k? What is the frequency of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

Step-by-step explanation:

Frequency of a mass-spring system is:

f = √(k/m) / (2π)

Given f = 2/π Hz and m = 20 kg:

2/π Hz = √(k / 20 kg) / (2π)

4 Hz = √(k / 20 kg)

16 s⁻² = k / 20 kg

k = 320 kg/s²

k = 320 N/m

If the 20 kg mass is replaced with an 80 kg mass, the frequency is:

f = √(320 kg/s² / 80 kg) / (2π)

f = √(4 s⁻²) / (2π)

f = 2 Hz / (2π)

f = 1/π Hz

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Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and
WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

n random sample taken (variable of interest)

\hat p=0.65 estimated proportion.

p true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=\pm 1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.06 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.65(1-0.65)}{(\frac{0.06}{1.64})^2}=169.968  

And rounded up we have that n=170

6 0
4 years ago
56+3<br><img src="https://tex.z-dn.net/?f=56%20%2B%203%20%3D%20" id="TexFormula1" title="56 + 3 = " alt="56 + 3 = " align="absmi
tangare [24]

sorry if I'm wrong. I got confused because you put 56+3 twice.×= 63
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I didnt know if that a subtracting or negative so here both

56+3=x-4 (this is with the negative sign)
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3 years ago
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erica [24]

Answer:

-14(5) = -70

9(-12) = -108

-6(-8) = 40

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3 years ago
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Lesechka [4]
I think the best option is 24.

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Answer:

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8 0
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