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Evgen [1.6K]
3 years ago
5

A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/p cycles/s, what is the spring const

ant k? What is the frequency of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

Step-by-step explanation:

Frequency of a mass-spring system is:

f = √(k/m) / (2π)

Given f = 2/π Hz and m = 20 kg:

2/π Hz = √(k / 20 kg) / (2π)

4 Hz = √(k / 20 kg)

16 s⁻² = k / 20 kg

k = 320 kg/s²

k = 320 N/m

If the 20 kg mass is replaced with an 80 kg mass, the frequency is:

f = √(320 kg/s² / 80 kg) / (2π)

f = √(4 s⁻²) / (2π)

f = 2 Hz / (2π)

f = 1/π Hz

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Answer:

4.9

Step-by-step explanation:

-6x2 = -144q

Divide both sides by -6

-6x2/-6 = -144/-6 q

X2 = 24q

Square root both sides

X = square root of 24q

X =4.9√q

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7 0
3 years ago
What is the distance between -45 and 65
tatyana61 [14]

Answer:

110

Step-by-step explanation:

What is the Difference between -45 and +65? In other words, what is the Difference between negative 45 and positive 65?

To solve this math problem, start by picturing a horizontal number line that starts with negative infinity on the left and ends with positive infinity on the right:

∞ ..... -3, -2, -1, 0, +1, +2, +3, .... ∞

The Difference between -45 and +65 is the distance between -45 and +65 on our number line above. Thus, the Difference between two numbers will always be a positive number.

It is a two-step process to calculate the Difference between -45 and +65. Step 1 is to subtract +65 from -45, and Step 2 is to find the absolute value of the Step 1 answer. Here is the math to illustrate better:

(-45) - (+65) = -110

|-110| = 110

That's it! The Difference between -45 and +65 is as follows:

110

5 0
3 years ago
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(f+g)(5)=33 is the answer
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3 years ago
There are twenty classes at Northwestern Middle School and twenty classes at Southeastern Middle School. The number of students
Contact [7]

Answer:

The means and medians are not the same. Or B

Step-by-step explanation:

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7 0
2 years ago
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In a small town in the Himalayas, the average snowfall each month is 6 inches. July is the month with the lowest average snowfal
OLga [1]

The function that models the above behavior is given as:

f(x) = ACos(B(x + C)) + 6 ..... .......i

where x = 1 (that is January)

D (Average Snowfall) = 6.

Hence, the amplitude (A) is given as:
A = 6-1

= 5

<h3>What is a mathematical function?</h3>

A mathematical function is a function comprising of different variables that    represent different factors or events and the relationships between them.

<h3>
During what period is there more than 10 inches of snowfall?</h3><h3 />

Recall that in a year we have 12 months. Hence, P = 12

→ P = (2π) /.B → (2π)/B = 12 → B = π/6

Taking the values of A and B and plugging them in, we ahve:

F(x) = 5 cos (π/6(x + C)) + 6................ii

This means that in July, we'll have

x = 7 and f(x) = 1

Therefore,

1 = 5cos ((π/6) (7 + C) + 6 → 5 Cos  ((π/6) (7 + C) →  -5cos ((π/6) (7 + C)

= -1

→   ((π/6) (7 + C) = π

→ 7 + C = 6

→ C = -1

Taking equation ii, we have

F(x) = 5cos ((π6) (x -1)) + 6

F (x) > 10

Therefore

5cos ((π/6) (x-1) + 6 > 10

→  cos ((π/6) (x-1) + 6 > 4/5

→  (π/6) (x-1)  > Cos⁻¹ (4/5)

(π/6) (x-1)  < 0.6435 and

(π/6) (x-1)  > 5.6397

→ x < 2.23 and x > 11.77

The interpretation is that upwards of ten inches of snow fall in January, February, November, and December.

Learn more about functions at;
brainly.com/question/25638609
#SPJ1

3 0
2 years ago
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