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GaryK [48]
3 years ago
6

Regina has started making baby quilts to sell at a craft fair. The inside of each quilt will measure four feet by five feet and

will be surrounded by a border of uniform width. She wants each quilt to have a total area (including the border) of 30 square feet. Find the equivalent equations to find the width of the border given that the border is x. Select all that apply.
1: (4+x)(5+x)=30
2: (4+2x)(5+2x)=30
3: 4x^2 + 20 = 30
4: 4x^2 +18x+20=30
5: (5+x)(4+x)=30
6:(x+4)(x+5)=30
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
Given are the statements describing the area of the baby quilts:

Inside dimensions = 4 x 5 feet
Border with uniform width = x feet
Total area of the quilt = 30 square feet

A = length x width

Area of inside quilt = 4 x 5
Area of quilt including the border = (4+2x) * (5+2x)

Therefore, the equations that are applicable are:

<span>2: (4+2x)(5+2x)=30
</span><span>4: 4x^2 +18x+20=30</span>
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morpeh [17]

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

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  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

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1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

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