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miss Akunina [59]
3 years ago
7

Solid potassium fluoride decomposes into fluorine gas and solid potassium .

Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

                2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

Explanation:

                    Chemical Formula of Potassium Fluoride  =  KF

                    Chemical Formula of Fluorine Gas  =  F₂

                    Chemical Formula of Solid Potassium  =  K

Step 1: Write the unbalance chemical equation,

                                             KF    →    F₂  +  K

Step 2: Balance Fluorine Atoms;

As there is one fluorine atom on left hand side and two fluorine atoms on right hand site therefore, to balance them multiply KF on left hand side by 2 i.e.

                                            2 KF    →    F₂  +  K

Step 3: Balance Potassium Atoms;

As there are two potassium atoms on left hand side and one potassium atom on right hand site therefore, to balance them multiply K on right hand side by 2 i.e.

                                             2 KF    →    F₂  +  2 K

Step 4: Assign Physical states as,

                                      2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

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Answer:

The correct answer is B.

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3 years ago
If 200 ml of 0.15 M propionic acid (PA) is added to 300 ml of 0.02 M NaOH, what is the resulting pH of the solution? Round the a
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Answer:

pH = 4.543

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  • CH3CH2COOH  + H2O ↔ CH3CH2COO-  +  H3O+
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⇒ Ka = 1.349 E-5 = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

added 300 mL 0f 0.02 M NaOH:

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⇒ <em>C</em> CH3CH2COOH = 0.048 M

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⇒ 0.048 + 0.012 = 0.06 M = [CH3CH2COO-] + [CH3CH2COOH].......(1)

charge balance:

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(2) in (1):

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replacing in Ka:

⇒ 1.349 E-5 = [H3O+][([H3O+] + 0.02) / (0.04 - [H3O+])

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Answer:

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Answer:



Explanation:



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