Answer:
The flow rate would be 22.5ml/hr
Explanation:
Volumetric flow rate = Mass flow rate ÷ density
Mass flow rate = 3mg/min = 3mg/min × 60min/1hr = 180mg/hr
Density = mass/volume = 2g/250ml = 0.008g/ml = 0.008g/ml × 1000mg/1g = 8mg/ml
Volumetric flow rate = 180mg/hr ÷ 8mg/ml = 22.5ml/hr
Answer:
The answer to your question is below
Explanation:
A.
[H₃O⁺] = 2 x 10⁻¹⁴ M
pH = ?
Formula
pH = - log [H₃O⁺]
Substitution
pH = - log [2 x 10⁻¹⁴]
Result
pH = 13.7
B.
[H₃O⁺] = ?
pH = 3.12
Formula
pH = - log [H₃O⁺]
Substitution
3.12 = - log [H₃O⁺]
![10^{-3.12} = [H_{3} O^{+}]](https://tex.z-dn.net/?f=10%5E%7B-3.12%7D%20%3D%20%5BH_%7B3%7D%20O%5E%7B%2B%7D%5D)
Result
[H₃O⁺] = 7.59 M
Density of boat =
=
= 0.88 g / cm³
Since the density of water is greater than the density of the boat ( 1 > 0.88) then that means,
the boat will NOT sink.B.
Answer:
2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.
Explanation:
Generally, moles of solute in solution before dilution must equal moles of solute after dilution.
By definition Molarity = moles solute/volume of solution in Liters
=> moles solute = Molarity x Volume (L)
Apply moles before dilution = moles after dilution ...
=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution
=> (M)(2.5L)before = (1.2M)(10.0L)after
=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate