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aalyn [17]
3 years ago
6

Which of the following is NOT a type of pseudoscience?

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
7 0
The answer is C. SETI
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Why does Hess's law allow you to determine the enthalpy change of a<br> reaction?
lana [24]

Enthalpy is a state function

Explanation:

The Hess's law allows us to determine the enthalpy change of a reaction because enthalpy is a state function. It does not depend on the individual path take in going from reactants to products in the reaction.

  • Enthalpy changes are the heat changes accompanying physical and chemical changes.
  • It is the difference between the heat content of product in the final state and the reactants.
  • Enthalpy changes for some reactions are not easily measurable experimentally.
  • To calculate such heat changes, we apply the Hess's law of heat summation.
  • The law states that "the heat change of a reaction is the same whether it occurs in a step or several steps".
  • The Hess's law is simply based on the first law of thermodynamics by which we know that energy is conserved in every system.

learn more:

Hess's law brainly.com/question/11293201

#learnwithBrainly

5 0
3 years ago
3. What methods are you using to test this hypothesis? Outline the steps of the procedure in full sentences.
Ulleksa [173]

Answer:

AHYPOTHISES IS A GUESS

Explanation:

4 0
3 years ago
When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac
slega [8]
<h2>Answer:</h2>1.33*10^{-2}grams

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}

Determine the mass of water produced

\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0
1 year ago
if a liquid is heated and the temperature at which it boils is measured, the ? property is being measured.
Serhud [2]
It would have to be physical property * if this helped you in anyway please be sure to leave a thanks:)
7 0
3 years ago
When a solution of beryllium sulfate and calcium hydroxide are mixed, what precipitate if any is formed
klasskru [66]

Answer:

CaSO₄ (calcium suflate) is the precipitate formed

Explanation:

We can think the reactants:

BeSO₄ → Beryllium sulfate

Ca(OH)₂ → Calcium hydroxide

The reaction is:

Be₂SO₄  +  Ca(OH)₂  →  CaSO₄ ↓  +  Be(OH)₂

We call it as a double-replacement reaction because two ions exchange places from 2 compounds to form two new compounds.

Sulfates can always make precipitate with the elements from group 2, Ca, Ba and Mg.  

Hydroxides from group 2 are solubles, so we complete states:

BeSO₄ (aq)  +  Ca(OH)₂ (aq)  →  CaSO₄ ↓ (s)  +  Be(OH)₂ (aq)

5 0
3 years ago
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