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aalyn [17]
3 years ago
6

Which of the following is NOT a type of pseudoscience?

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
7 0
The answer is C. SETI
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Acid indigestion is sometimes neutralized with an antacid such as magnesium hydroxide (Mg(OH)2). What products will be released
Lunna [17]

Answer: d) MgCl_2 and H_2O​

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

A neutralization reaction is a double displacement reaction in which an acid reacts with base to produce salt and water. The H^+ ions from water reacts with OH^- ions from base to give water.

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

Thus products that will be released when the antacid is mixed with the hydrochloric acid in the stomach are MgCl_2 and H_2O​

3 0
3 years ago
PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!
Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

95

mL of water.

8 0
3 years ago
Identify the family to which the compound (h3c−ch2oh) belongs. identify the family to which the compound (a) belongs. alcohol et
OLga [1]
Each of the organic compounds mentioned has a general formula so that we can identify the classification of a certain substance. The compound CH₃CH₂OH is an alcohol because it follows the general formula R-OH, where R is a hydrocarbon chain. In this case, the hydrocarbon chain is ethane. When a hydroxyl functional group is attached, it becomes an alcohol whose name is ethanol.
5 0
4 years ago
Read 2 more answers
What is the average atomic weight of silver?​
Natali5045456 [20]

Answer:

107.8682 u would be the answer

Explanation:

8 0
3 years ago
Read 2 more answers
N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
3 years ago
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