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4 years ago

6

Which of the following is NOT a type of pseudoscience?

1 answer:

s344n2d4d5 [400]4 years ago

7 0

The answer is C. SETI

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If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol

Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity :

$v_{rms}=\sqrt{\frac{3RT}{M}}$

$K.E_{avg}=\frac{3}{2}RT$

$K.E =\frac{1}{2}mv_{rms}^{2}$

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

$K.E_{avg}=\frac{3}{2}RT$

$T=\frac{2(K.E)}{3(R)}$

K.E of He = 4310 J/mol

$T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}$

$T=345.60K$

<u>Now , Use Vrms to calculate the velocity of O2</u>

$v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}$

$v_{rms}=\sqrt{\frac{8619.9552}{0.032}}$

$v_{rms}=\sqrt{26935.001}$

$v_{rms}=519.01m/s$

6 0

4 years ago

N which direction will the net reaction proceed.

finlep [7]

Answer:

1) The correct answer is option b.

2) The correct answer is option a.

Explanation:

1)

$X+Y\rightleftharpoons Z$

At 300 K, the value of the $K_p=1.00$

The $K_c$ and $K_p$ is related by :

$K_p=K_c\times (RT)^{\Delta n}$

where,

$K_p$ = equilibrium constant at constant pressure

$K_c$ = equilibrium concentration constant

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 300 K

$\Delta n$ = change in the number of moles of gas = 1 - 2 = -1

Now put all the given values in the above relation, we get:

$1.00=K_c\times (0.0821 L atm/(K mol)\times 300)^{-1}$

$K_c=24.63$

The $K_c$ of the reaction = 24.63

Given = [X] = [Y] = [Z] = 1.0 M

Value of reaction quotient = Q

$Q=\frac{[Z]}{[X][Y]}=\frac{1.0 M}{1.0M\times 1.0 M}=1$

$Q$ , the equilibrium will move in forward direction that is in the right direction.

2)

$X+Y\rightleftharpoons Z$

At 300 K, the value of the $K_p=1.00$

Given = $P_x = P_z = 1.0 atm, P_y = 0.50 atm$

Value of reaction quotient in terms of partial pressure = $Q_p$

$Q_p=\frac{P_z}{P_x\times P_y}=\frac{1.0 atm}{1.0 atm\times 0.50 atm}$

$Q_p=2$

$Q_p>K_p$ the equilibrium will move in backword direction that is in the left direction.

6 0

3 years ago

The scientific evidence that scientists use in supporting or critiquing the conclusions of experiments usually consists of

ohaa [14]

The scientific evidence that scientists use in supporting or critiquing the conclusions of experiments usually consists observations based on large sample sizes.

5 0

3 years ago

The [H+] in solution is 1.0 X 10-3 M. This solution is BEST classified as

N76 [4]

I’m not sure but I think the right is neutral or it’s could be acidic

8 0

3 years ago

Read 2 more answers

when you hold a metal coat hanger in a camp fire to roast a marshmallow, the coat hanger might get too hot to hold. what type of

JulsSmile [24]

Answer:

Heat transfer by conduction

3 0

3 years ago