Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Answer:
15
Step-by-step explanation:
30% of 50 is 15 beacuase 50 is 1/2 of 100, and of 100 students 30 would have submtted forms. 1/2 of 30 is 15 which s the number of students that turned n forms
Answer:
120cm^3
Step-by-step explanation:
Answer:
f(x) , r(x), t(x)
Step-by-step explanation: