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Nataliya [291]
3 years ago
11

You are trying to determine the half-life of a new radioactive element you have isolated. You start with 1 gram, and 5 days late

r you determine that it has decayed down to 0.6 grams. What is its half-life?
Mathematics
1 answer:
Oliga [24]3 years ago
5 0
Half-life = elapsed time * log(2) / log (bgng amt / ending amt)
half-life = (5 * <span> <span> <span> 0.3010</span></span></span>3) / log (1/.6)
half-life = (5 * <span> <span> 0.3010</span></span>3) / log (1/.6)
<span>half-life = 1.505 / </span> <span> <span> <span> 0.221848750 </span> </span> </span>
half-life = <span> <span> <span> 6.785 days
Location for formulas & calculator
http://www.1728.org/halflife.htm

</span></span></span>
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A cylindrical paint can has a capacity of one gallon. for another size can, the height is doubled. what is the capacity of the l
skelet666 [1.2K]
We know that

[volume of a <span>cylindrical paint can 1]=[area of the base]*h
so
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if <span>the height is doubled
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4 0
3 years ago
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Answer:

\boxed{\mathfrak{Question ~}}

What is the degree of polynomial?

\large\boxed{\mathfrak{Answer}}

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3 0
2 years ago
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Delicious77 [7]

Answer:

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3 years ago
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