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Nataliya [291]
3 years ago
11

You are trying to determine the half-life of a new radioactive element you have isolated. You start with 1 gram, and 5 days late

r you determine that it has decayed down to 0.6 grams. What is its half-life?
Mathematics
1 answer:
Oliga [24]3 years ago
5 0
Half-life = elapsed time * log(2) / log (bgng amt / ending amt)
half-life = (5 * <span> <span> <span> 0.3010</span></span></span>3) / log (1/.6)
half-life = (5 * <span> <span> 0.3010</span></span>3) / log (1/.6)
<span>half-life = 1.505 / </span> <span> <span> <span> 0.221848750 </span> </span> </span>
half-life = <span> <span> <span> 6.785 days
Location for formulas & calculator
http://www.1728.org/halflife.htm

</span></span></span>
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3 years ago
While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between
aleksandr82 [10.1K]

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable <em>X</em> denote the water depths.

As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

P(2.25

                               =\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55

Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

6 0
3 years ago
What is 975, 462 round to the nearest hundred thousand
podryga [215]

Answer:

it would be 1 million, ( 1,000,000 )

Step-by-step explanation:

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5 0
3 years ago
Help me plz i don't understande
Misha Larkins [42]
Multiply 8 by 4 and that will give you 32 then add 9 and you get 41 so the answer is 41 years old
6 0
3 years ago
Read 2 more answers
The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

6 0
3 years ago
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