Answer:
I think it is 6/7
Step-by-step explanation:
I am really bad at explaining but I'm not completely sure
Answer:
A. 2086 yd²
Step-by-step explanation:
SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)
Given :
Population of country in 2006 , P = 300 million.
Consumption of fruit juice in 2006 by while population, C = 1.85 billion.
To Find :
The average number of gallons of fruit juice consumed per person in the country in 2006.
Solution :
We know, 1 billion = 1000 million.
C = 1.85 billion = 1850 million.
Now, average umber of gallons of fruit juice consumed per person in the country in 2006 is :
Hence, this is the required solution.
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Answer:
625/2401
Step-by-step explanation:
5/7 ^ 4 = 5 * 5 * 5 * 5 / 7*7*7*7 = 625/2401
