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Nuetrik [128]
3 years ago
13

A strand of hair is approximately 50 μm thick. If the diameter of an atom is 1 × 10-10 m, how many atoms thick is a strand of ha

ir?
Chemistry
2 answers:
Kazeer [188]3 years ago
6 0

Thickness of strand hair = 50 μm

Diameter of an atom  = 1 \times 10^{-10} m

Now, with the help of conversion factors, convert thickness in micrometer into meter i.e. 1 micrometer = 10^{-6}m

So, thickness of strand hair =50 μm= 50 \times 10^{-6} m

Therefore,

number of atoms thick is a strand of hair =  50 \times 10^{-6}m\times \frac{1 atom}{1 \times 10^{-10}m}

= 50\times 10^{4}atoms

Hence, number of atoms is 50\times 10^{4}atomsthick is a strand of hair.


alexandr402 [8]3 years ago
6 0

Answer : The number of atoms thick in a strand of hair are 5\times 10^5\text{ atoms}

Explanation : Given,

Diameter of an atom = 1\times 10^{-10}m

Thickness of strand of hair = 50\mu m=50\times 10^10^{-6}m

conversion used : 1\mu m=10^{-6}m

Now we have to determine the number of atoms thick in a strand of hair.

\text{Number of atoms thick}=\frac{50\times 10^10^{-6}m}{1\times 10^{-10}m}=5\times 10^5\text{ atoms}

Therefore, the number of atoms thick in a strand of hair are 5\times 10^5\text{ atoms}

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Answer:

ΔS = +541.3Jmol⁻¹K⁻¹

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Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹

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Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹

Standard Entropy of CO = 198Jmol⁻¹K⁻¹

To find the entropy change of the reaction, we first write a balanced reaction equation:

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To calculate the entropy change of the reaction we simply use the equation below:

      ΔS = ∑S_{products} - ∑S_{reactants}

Therefore:

     ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1

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3 years ago
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a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
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The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

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We know that 1 ppm is equal to 1 mg/L.

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The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

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Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

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You will need to prepare 12 mL of 25% Sodium Phosphate Buffer (pH 4) solution for Activity 2. What volume of the stock Sodium Ph
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Assuming the concentration of stock solution is 50% sodium phosphate buffer solution, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.

<h3>What volume of a stock Sodium phosphate buffer and water is needed to 12 mL of 25% sodium phosphate buffer of pH 4?</h3>

The process of preparing solutions from stock solutions of higher concentration is known as dilution.

Dilution is done with the aid of the dilution formula given below:

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Learn more about dilution formula at: brainly.com/question/7208546

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