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Serhud [2]
3 years ago
8

Given the Vapour Density of a hydrocarbon is 150, what is it's molecular formula.​

Chemistry
1 answer:
Anna35 [415]3 years ago
6 0
Molecular formula = C4H10.

or

Simplest ratio
Empirical formula mass = 12 1 + 1 1+ 16 1 = 29.

Molecular mass = 2 vapour density. = 2 58. = 116.

Molecular formula mass = n Empirical formula mass.

Molecular formula = n Empirical formula.

= 4 (CHO)
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Write 0.00103 in scientific notation
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Answer:

1.03

Explanation:

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During an investigation, a student burns magnesium to form magnesium oxide. The starting mass of magnesium is measured as 21.3 g
enot [183]

Answer:

Percentage yield = 85.2%

Explanation:

Given data:

Mass of Mg = 21.3 g

Actual yield of MgO = 30.2 g

Percentage yield = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

Number of moles of Mg = mass/molar mass

Number of moles of Mg = 21.3 g / 24.3 g/mol

Number of moles of Mg = 0.88 mol

Now we will compare the moles of MgO with Mg.

                 Mg           :               MgO

                 2               :               2

                0.88             :             0.88

Mass of MgO:           

Mass of MgO= moles × molar mass

Mass of MgO= 0.88 mol × 40.3g/mol

Mass of MgO =  35.46 g

Actual yield of MgO = 30.2 g

Percentage yield:

Percentage yield = Actual yield/theoretical yield × 100

Percentage yield = 30.2 g/ 35.46 g × 100

Percentage yield = 85.2%

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Answer:

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Their identity changes in both Reaction A and Reaction B.

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