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Alinara [238K]
3 years ago
15

What is the fifth term of (3 - x)^6?

Mathematics
1 answer:
Andrej [43]3 years ago
4 0
0909 becaue jdnjasccnmds enscdbjsdn
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Is this done correctly or incorrectly??<br> PLEASE LET ME KNOW<br><br>PLZ HELP ASAP
Dimas [21]
You're very close. However, the less steep line should go through (4,7) and not some point slightly above that location. Also, the shaded region should be above both dashed lines at the same time. So you won't include the portion that I've marked in blue (see attached). Other than that, it looks great. 

3 0
3 years ago
The bottom of a box is to be a rectangle with a perimeter of 36 CM. The Box must be 4 cm High. What is the maximum volume?
Amanda [17]

The maximum volume would be when the bottom of the box is a square.

The perimeter of the bottom is 36, so the side of the square would be 36/4 = 9 cm.

Then to find volume multiply the length by the width by the height:

Volume = 9 x 9 x 4 = 324 cm^3

The answer would be a.

8 0
3 years ago
Read 2 more answers
F(x)=(5x+3)(x−2)(3x+7)(x+5) has zeros at x = -5, x = -7/3, x = 2
musickatia [10]

The sign of f on the interval -7/3 < x < -3/5 is always positive.

<h3>How to solve for the sign on the interval</h3>

We have the equation

(5x+3)(x−2)(3x+7)(x+5) > 0

Now when f(x) > 0

Then -7/3 < x < -3/5

This would tell us that the sign would become positive when it changes from the less than to greater than sign

<h3>Complete Question</h3>

f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2

What is the sign of f on the interval -7/3<x<-3/5?

answer choices

f is always positive on the interval

f is always negative on the interval

f is sometimes positive and sometimes negative on the interval

f is never positive or negative on the interval

Read more on polynomials here:

brainly.com/question/2833285

#SPJ1

5 0
2 years ago
Suppose the wholesale price of a certain brand of medium-sized eggs p (in dollars/carton) is related to the weekly supply x (in
Mrrafil [7]

Answer:

1300

Step-by-step explanation:

We are given

x = 35

\frac{dp}{dt}=-0.05  [rate of change of price with time]

We want to find \frac{dx}{dt}, which is the rate at which supply is changing.

First, we need to implicitly differentiate the equation given:

625p^2-x^2=100\\1250p\frac{dp}{dt}-2x\frac{dx}{dt}=0

Here, we have what we need except for p. We find p when x = 35:

625p^2 - x^2 =100\\625p^2 - (35)^2 =100\\625p^2=1325\\p=1.46

Now, find dx/dt:

1250(1.46)(-0.05)-2(35)\frac{dx}{dt}=0\\-91.25-70\frac{dx}{dt}=0\\\frac{dx}{dt}=-1.30

In thousands, 1.30 * 1000 = 1300 cartons per week decrease

5 0
3 years ago
Need help on both of these for geometry
artcher [175]

Answer:

Step-by-step explanation:

have the triangles written in the same order to se the corresponding angles

C      A .   T

⇵ .  ⇵ .   ⇵

D      O .   G

∠D ≅∠C

∠O ≅∠A

GD ≅TC

10.

you have an isosceles triangle with vertex angle 48 so the base angle is

(180-48)/2 = 66

32+ x = 66 because is an exterior angle

x= 66-32 = 34

4 0
3 years ago
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