All categories

3 years ago

What is the fifth term of (3 - x)^6?

1 answer:

4 0

0909 becaue jdnjasccnmds enscdbjsdn

You might be interested in

Fynjy0 [20]

Answer:

9.30918

Step-by-step explanation:

3 0

3 years ago

Harman [31]

Answer:

a) Yes, the two variables correlated

b) Yes, variation of sugar changes the number of orders for item containing sugar

Step-by-step explanation:

a) Yes the two variables are moderately co-related as the value of co-relation lies between 0.5 and 0.7

b) Yes the variation in amount of sugar leads to variation in the number of orders with sugar.

8 0

3 years ago

alisha [4.7K]

I am still not getting my phone back to my computer and my phone and I am trying to find out what

4 0

3 years ago

Korolek [52]

3/12 + 10/12 = 13/12 because the points lie in-between the 1/6 and 2/6 marks and the 6/6 and 7/6 marks.

6 0

4 years ago

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago