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melamori03 [73]
3 years ago
12

The gravitational potential energy of an object is

Mathematics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

h=p/(mg)

Step-by-step explanation:

P=mgh

solving for h,

h=p/(mg)

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I need help with this I don't get it at all
iren [92.7K]

Answer:

the answer is C

Step-by-step explanation:

because the negative needs to be on the inside not on the outside

8 0
3 years ago
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The total weight of 9 bags of potatoes is 36 kilograms each bag weights the same amount what is the weight in grams of each bag
ra1l [238]

Answer:

4000

Step-by-step explanation:

36kg = 36000g

36000g/9 bags = 4000g

5 0
3 years ago
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Instructions: Drag the tiles to the correct boxes to complete the pairs.
snow_tiger [21]
7/5y= y+2/5y
0.68y = y-0.32y
3/5y=y-2/5y
1.32y=y+0.32y
8 0
3 years ago
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use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
A newspaper found that, on average, 7.6% of people stay overnight in the hospital with a 1.5% margin of error. Construct a 95% c
tensa zangetsu [6.8K]
Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.

The standard error is 
Es = \sqrt{ \frac{p(1-p)}{n} }
where 
n =  the sample size.

The margin of error is
E=z^{*}E_{s}
where
z* = 1.96 at the 95% confidence level.

Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)

Answer: 
The 95% confidence interval is between 6.1% and 9.1%.

3 0
4 years ago
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