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3 years ago

What volume of .2500 m cobalt iii chloride is required to react completely with 25 ml of .0315 m calcium hydroxide?

1 answer:

8 0

<span>f 0.0315 M calcium hydroxide?<span>Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react

could you mark as brailiest</span></span>

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What color dose red cabbage juice turn when it is mixed with lemon juice

miss Akunina [59]

I think it’s green but idk

7 0

3 years ago

A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising spee

zmey [24]

Answer:

The average power delivered by the elevator motor during this period is 6.686 kW.

Explanation:

Given;

mass of the elevator, m = 636 kg

initial speed of the elevator, u = 0

time of motion, t = 4.5 s

final speed of the elevator, v = 2.05 m/s

The upward force of the elevator is calculated as;

F = m(a + g)

where;

m is mass of the elevator

a is the constant acceleration of the elevator

g is acceleration due to gravity = 9.8 m/s²

$a = \frac{v-u}{t} \\\\a = \frac{2.05 -0}{4.5} \\\\a = 0.456 \ m/s^2$

F = (636)(0.456 + 9.8)

F = (636)(10.256)

F = 6522.816 N

The average power delivered by the elevator is calculated as;

$P_{avg} = \frac{1}{2} (Fv)\\\\P_{avg} = \frac{1}{2} (6522.816 \ \times \ 2.05)\\\\P_{avg} = 6685.89 \ W\\\\P_{avg} = 6.68589 \ kW\\\\P_{avg} = 6.686 \ k W$

Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.

3 0

2 years ago

A bungee cord with a spring constant of 800 stretches 6 meters at its greatest displacement. How much elastic potential energy d

Vinil7 [7]

Elastic potential energy is given by formula

$U = \frac{1}{2} kx^2$

here we know that

$k = 800 N/m$

$x = 6 m$

Now using above formula we have

$U = \frac{1}{2}(800)(6^2)$

$U = 14400 J$

So elastic potential energy in the chord is 14400 J

4 0

3 years ago

An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction  between the object and th

Gnom [1K]

Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

Note: lost KE is converted to work done against the friction + PE of the spring

1/2mv2 = μmgx + 1/2kx^2....equation i

Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

Due to frictional effect, further enegy will be lost when the spring recoils backward

Therefore

1/2kx^2 = μmgx..... equation ii

Let's substitute 1/2kx^2 in equation I for ii

So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

k = 8m * (μg/v)^2

8m * (μg/v)^2

7 0

2 years ago

During a move, Jonas and Matías carry a 115kg safe to the third floor of a building, covering a height of 6.6m.

neonofarm [45]

Answer:

work is =7590joules

power = 23watts

4 0

3 years ago

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