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3 years ago

What volume of .2500 m cobalt iii chloride is required to react completely with 25 ml of .0315 m calcium hydroxide?

1 answer:

8 0

f 0.0315 M calcium hydroxide?Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react

could you mark as brailiest

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Which of the following equations can be used to directly calculate an object's impulse?

Iteru [2.4K]

I believe the answer is B

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4 years ago

22. (I) A car slows down from 28 m/s to rest in a distance of

lidiya [134]

Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

v = d/t

∴ t = d/v

Substituting in the above values in the given equation

t = 88/28

= 3.142 s

The acceleration is given by the formula

a = (v-u)/t

= (0 - 28)/3.142

= -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

7 0

4 years ago

Melissa and Rory live near a bike trail, 21 km apart. They plan to meet at a park mid-way between their homes. They start from t

DiKsa [7]

Answer:

27km.

Explanation:

Jessie will run for a duration of time, which is the time it takes for Melissa and Rory to meet each other.

Together combined, Melissa and Rory runs at 14km/h. The bike trail is 21km, so it will take 1.5 hours.

Jessie runs at 18km/h, so Jessie will run 18 * 1.5 = 27km.

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3 years ago

A person hears sound wave beast at 3000Hz at the temperature of 30 °C. What is the person's ear canal length? Please explain

Evgen [1.6K]

Answer:

The person's ear canal length is 2.91 cm.

Explanation:

Given that,

Frequency = 3000 Hz

Temperature = 30°C

We need to calculate the speed

Using equation of sound wave with temperature

[texs]v(t)=331+0.6\times T[/tex]

Put the value of T

$v(t)=331+0.6\times30^{\circ}\ C$

$v(t)=349\ m/s$

We need to calculate the length

Using formula of closed organ pipe

$f=\dfrac{v}{4L}$

$L=\dfrac{v}{4f}$

Where, L = length

v = velocity

f = frequency

Put the value into the formula

$L=\dfrac{349}{4\times3000}$

$L=0.0291\ m$

$L=2.91\times10^{-2}\ m$

$L=2.91\ cm$

Hence, The person's ear canal length is 2.91 cm.

4 0

3 years ago

the highest directly measured frequency is 5.20 x 10^14 Hz, corresponding to one of the transitions in iodine-127. How many wave

Thepotemich [5.8K]

λ = 5.7 X 10⁻⁷m

On using quantum dot, it is 351

Explanation:

Given-

Frequency, f = 5.20 x 10^14 Hz

Speed of light, c = 3 X 10⁸ m/s

Wavelength, λ = ?

We know,

λ f = c

λ = c / f

λ = $\frac{3 X 10^8}{5.2 X 10^1^4}$

λ = 5.7 X 10⁻⁷m

Dot = 2 X 10⁻⁴

So,

2 X 10⁻⁴ / 5.7 X 10⁻⁷m = 351

8 0

4 years ago