The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
The first graph is B. x^2 + 6 < 3
It is a parabola and opens upward when x^2 is positive. 6 raises it upwards by 6 units. the circle at
x = 3 means that the function can approach but not be equal to 3.
The answer is b I believe
B. $27,000
I hope helped ^-^
Answer:
1 / 8², B
Step-by-step explanation:
8 / 8³
8³ = 8*8*8
So, the equation can also be written as:
8 / 8*8*8
divide the numerator and denominator by 8.
1 / 8*8
This is equal to:
1 / 8²
The answer is B.
