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4 years ago

10

The density of mercury is 13.6 g/cm3. Therefore, the specific gravity of mercury is 13.6.

1 answer:

Orlov [11]4 years ago

8 0

False the gravity on mercury is 3.7 m/s²

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Xander claims that since the model of the atom has been changed so many times, that means it is a weak model. Willow claims that

uranmaximum [27]

Willow is right because the model of atom is not weak. The model of the atom has not changed. It’s just due to new discoveries due to which atom’s model is changing. The particles were always present in the atom but we were not able to discover it.

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4 years ago

SIZIF [17.4K]

Answer:

The term reduction means you are reducing the componenets of the air.

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

6 0

3 years ago

Which of the following can be used to neutralize a sodium hydroxide (NaOH) solution? NaCl NH3 HCl Ca(OH)2

Andru [333]

NaOH is a base and hence it can only be neutralized by an acid.

So it is by HCl, which is an acid.

4 0

3 years ago

Read 2 more answers

What gas comes off it

Andreyy89

Answer:

the answer to this question is hydrogen gas

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3 years ago