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NemiM [27]
3 years ago
11

The compound CaSO4 ionizes into a calcium ion and a sulfate ion (SO4). Calcium has two electrons in its outer shell. Upon ioniza

tion, what would you expect the charge on the sulfate ion to be?
Chemistry
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

-2

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Thus, calcium loses two electrons to sulfate ion and sulfate ion accepts these electrons to form ionic bond.

Calcium sulfate, CaSO_4 is formed when 2 valence electrons of calcium are loosed and they are gained by sulfate ion.

Ca^{2+}+SO_4^{2-}\rightarrow CaSO_4

Thus, the charge on the sulfate ion is -2.

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One mole of silver has a mass of 107.9 grams. Approximately how many atoms of silver are present in one mole of silver
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Answer: Silver has an atomic mass of aproximately 107.9.

Explanation:

1 mole of silver atoms = 107.9g and there are 6.02x10^23 atoms in one mole.

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It is the gametes formation of a sex cells or reproductive cells.​
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Using molecular orbital theory, the bond order of the C-C bond in the C2 molecule is _____. g
In-s [12.5K]

Answer:

The bond order for C2 molecule is 2.

Explanation:

Bond order can be defined as the half of the difference between the number of electrons in the bonding orbital and the number of electrons in the antibonding orbitals. It can be represented mathematically by; .

Bond order,n= [number of electrons in the bonding molecular orbitals(BMO) - the number or electrons in the anti-bonding molecular orbitals(AMO) ] / 2.

The electronic configuration of the C2 molecule is given below;

C2 = (1sσ)^2 (1s^*σ)^2 (2sσ)^2 (2s^*σ)^2 (2pπ)^4.

The ones with the (*) are known as the Anti-bonding molecular orbitals while the ones without (*) are known as the bonding molecular orbitals. Hence, we have 8 Electrons from the bonding molecular orbitals and 4 Electrons from the anti-bonding molecular orbitals.

So, from the formula given above, the bond order of C2 molecule is;

===> 8-4/2= 4/2.

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7 0
2 years ago
1. If a car is traveling 90 mi/hr, how many feet will the car travel in 1 sec? In 5 sec?
Fudgin [204]

Answer:

The car travel 660 feet

Explanation:

First convert the Speed into <u>Feet/sec</u>

Speed of the car = 90 mi/hr

1 mi = 5280 ft

In 90 miles = 90 x 5280 = 475,200  feet

1 hr = 60 min

1 min = 60 sec

So ,

1 hr = 60 x 60 sec = 3600 sec

The speed is defined as the distance traveled by the object in unit time. The formula of speed is :

Speed =\frac{distance}{time}

Speed =\frac{90mi}{1hr}... given

Speed =\frac{475200 ft}{3600sec}

Speed = 132 ft/sec

Now,  time = 5 sec

Speed =\frac{distance}{time}

distance =speed\times time

distance = 132ft/sec\times 5sec

Distance = 660 feet

3 0
3 years ago
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