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NemiM [27]
3 years ago
11

The compound CaSO4 ionizes into a calcium ion and a sulfate ion (SO4). Calcium has two electrons in its outer shell. Upon ioniza

tion, what would you expect the charge on the sulfate ion to be?
Chemistry
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

-2

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Thus, calcium loses two electrons to sulfate ion and sulfate ion accepts these electrons to form ionic bond.

Calcium sulfate, CaSO_4 is formed when 2 valence electrons of calcium are loosed and they are gained by sulfate ion.

Ca^{2+}+SO_4^{2-}\rightarrow CaSO_4

Thus, the charge on the sulfate ion is -2.

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What mass of solid lead would displace exactly 234.6 liters of water?
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The mass of solid lead would displace exactly 234.6 liters of water should be <span>2,674,440</span>
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Table salt contains 39.33 g of sodium per 100 g of salt. The U.S. Food and Drug Administration (FDA) recommends that adults cons
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The  individual can consume less than 184.6 g of the snack mix and still be within the FDA limit of salt consumption.

<h3>What is the mass of snack that can be consumed within the limit of sodium intake?</h3>

The mass of the snack mix that the individual can consume and still be within the FDA limit is calculated as follows:

U.S. Food and Drug Administration (FDA) recommends of sodium intake = less than 2.40 g of sodium per day.

Amount of salt in 100 g of snack mix = 1.30 g

Mass of snack that will contain 2.40 g of sodium = 2.40 * 100g/1.30 = 184.6 g of snack mix

Therefore, the individual can consume less than 184.6 of the snack mix and still be within the FDA limit of salt consumption.

In conclusion, the FDA recommends that an individual take in less than 2.40 g of sodium per day from their diet.

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7 0
1 year ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
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