Answer:
Height through the water falls h = 33 m
Efficiency of the of the unit
η
=
80
%
Power of the production unit
P
=
45
×
10
6
W
Acceleration due to gravity
g
=
9.8
m
/
s
Potential energy of one kg of water
Δ
U
=
m
∗
g
∗
h
=
1
∗
9.8
∗
33
=
323.4
J
Eighty percentage of the above energy is converted into electrical energy.
So eighty percentage of the potential energy of one kg of water
Δ
U
1
=
258.72
J
So mass of water required to flow per second to produce 45 MW of electricity in kilograms
M
=
P
Δ
U
1
=
45
∗
10
6
258.72
=
173933.2096
k
g
/
s
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Hydroelectric Energy: Definition, Uses, Advantages & Disadvantages
from Earth Science 101: Earth Science
Chapter 23 / Lesson 9
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