Explanation:
The primary reason for this is efficiency. In most applications, a lower resistance means less power is converted to heat and lost to the surrounding environment and more of the supplied power gets to its intended destination.
I’ll refer to electromagnetic radiation as EMR.
Visible light is a very small subset of EMR. Many other ranges like infrared, ultraviolet, or gamma must be detected by special equipment.
EMR is what makes up light, and as we know from any high school physics class, light exhibits both particle-like properties (photoelectric effect and Compton scattering) and wave-like properties (refraction, diffraction, double-slit & single-slit experiment).
EMR can travel without a medium, like the vast emptiness of space. It can also travel with a medium. It can transmit through various materials albeit at a slower speed, like water, earth’s atmosphere, glass etc.
The propagation speed of EMR in space is 3x10^8 m/s, which is a speed unattainable by any of our current means of transportation. I would say that’s quite fast.
Answer:
minimum length of runway is needed for take off 243.16 m
Explanation:
Given the data in the question;
mass of glider = 700 kg
Resisting force = 3700 N one one glider
Total resisting force on both glider = 2 × 3700 N = 7400 N
maximum allowed tension = 12000 N
from the image below, as we consider both gliders as a system
Equation force in x-direction
2ma = T -f
a = T-f / 2m
we substitute
a = (12000 - 7400 ) / (2 × 700 )
a = 4600/1400
a = 3.29 m/s²
Now, let Vf be the final speed and Ui = 0 ( as starts from rest )
Vf² = Ui² + 2as
solve for s
Vf² = 0 + 2as
2as = Vf²
s = Vf² / 2a
given that take of speed for the gliders and the plane is 40 m/s
we substitute
s = (40)² / 2×3.29
s = 1600 / 6.58
s = 243.16 m
Therefore, minimum length of runway is needed for take off 243.16 m
