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sergiy2304 [10]
3 years ago
7

The area of triangle LMN is 45 in². What is the area of the parallelogram LMNO? A.45 in² B. 90 in² C. 135 in² D.180 in²

Mathematics
1 answer:
krok68 [10]3 years ago
7 0

Answer:its A.

Step-by-step explanation:

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6+[11-{10+2-(8 of 2+1-3×4) }]
Vesna [10]

Answer:

17

Step-by-step explanation:

Step-by-step explanation:

6+[11-{10+2-(8×2+1-3×4)}]

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)}

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)} ]6+[11-[10+2-12}]

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)} ]6+[11-{10+2-12}]6+[11-{0}]

6+[11-0]

6+[11]

6+11

17 Ans.

7 0
3 years ago
Cashews cost $6.45 a
almond37 [142]

Answer:

$20.96

Step-by-step explanation: 6.45 times three equals 19.35 plus a quarter of 6.45 equals 1.6125 which you round to 1.61. So 19.35+1.61= 20.96

8 0
3 years ago
P is the midpoint of XY x p equals 8 x - 2 + p y equals 12x - 30 find the value of x​
disa [49]

Answer:

but please give me and please mark me as

7 0
3 years ago
This doesn’t make sense explain plz
AnnZ [28]

Its simple, graph them.

For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.

For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.

When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.

I hope this cleared up your confusion, brainliest/heart would help.

5 0
2 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
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