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3 years ago

Find the poing of center of gravityplz show the steps...

Physics

1 answer:

olasank [31]3 years ago

7 0

Answer:

Explanation:

For a uniformly distributed mass, the center of gravity is also the geometric center. For this shape, the center is at point C.

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If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)

worty [1.4K]

Answer: $\sqrt{2}$

The linear momentum $p$ is given by the following equation:

$p=m.v$ (1)

Where $m$ is the mass and $v$ the velocity.

On the other hand, the kinetic energy $K$ is given by:

$K=\frac{p^{2}}{2m}$ (2)

Which is the same as:

$K=\frac{1}{2}m.v^{2}$

Now, if we double the kinetic energy, equation (2) changes to:

$2K=2\frac{p^{2}}{2m}$

$2K=\frac{p^{2}}{m}$ (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of $\sqrt{2}$ or $2^{1/2}$ :

Applying this in (2):

$K=\frac{(\sqrt{2}p)^{2}}{2m}$

$K=\frac{(2p)^{2}}{2m}$

$K=\frac{p^{2}}{m}$ >>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0

3 years ago

Activity 4:

3241004551 [841]

Answer:

1.so that we won't do any mistakes and won't have injuries.

Explanation:

yes.

because it is a right thing to use correct tools for correct work.

4 0

3 years ago

A viscous fluid is flowing through two horizontal pipes. They have the same length, although the radius of one pipe is three tim

Rudik [331]

The conservation of the mass of fluid through two sections (be they A1 and A2) of a conduit (pipe) or current tube establishes that the mass that enters is equal to the mass that exits. Mathematically the input flow must be the same as the output flow,

$Q_1 = Q_2$

The definition of flow is given by

$Q =VA$

Where

V = Velocity

A = Area

The units of the flow of flow are cubic meters per second, that is to say that if there is a continuity, the volume of input must be the same as that of output, what changes if the sections are modified are the proportions of speed.

In this way

$Q_A = Q_B$