The transfer of energy by electromagnetic

A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0 N. What is the speed of the wave?

enyata [817]

The speed of a wave is determined by the product of the frequency and the wavelength; we already have the wavelength and the frequency, so all we need to do is multiply them by each other and use our proper unit of measure.

Velocity (speed) = Frequency x Wavelength
V = 250 x 6
V = 1500

Your answer is 1500 m/s.

I hope this helps!

5 0

3 years ago

A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an

Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0

3 years ago

A mail carrier leaves the post ofﬁce and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00

den301095 [7]

Answer:

$\theta=7^o$

Explanation:

<u>Displacement</u>

It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.

The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

$\vec r_1=\ km$

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

$\vec r_2=\ km=\ km$

Finally, he drives 9.5 km 35° north of east.

$\vec r_3=\ km=\ km$

The total displacement is

$\vec r_t=\ km+\ km+\ km$

$\vec r_t=\ km$

The direction can be calculated with

$\displaystyle tan\theta=\frac{1.39}{11.28}=0.1232$

$\boxed{\theta=7^o}$

7 0

3 years ago

A radio receiver has an effective resistance of 300 Ω to the input signal on the antenna downlead. The signal voltage is 700 µV.

White raven [17]

Answer:

I = 2.33 µA

Explanation:

given,

Effective resistance (R)= 300 Ω

Voltage of signal (V)= 700 µV

current flow in the antenna = ?

Using ohm's law

V = I R

where I is the current flow

$I = \dfrac{V}{R}$

$I = \dfrac{700\times 10^{-6}}{300}$

I = 2.33 x 10⁻⁶ A

I = 2.33 µA

Hence, the current flow in the antenna downloaded is equal to I = 2.33 µA

6 0

3 years ago

Read 2 more answers

A wave is traveling at a speed of 15 m/s and it's wavelength is 5 m. Calculate the waves frequency

Anvisha [2.4K]

Answer:

The frequency of this wave is $3\; \rm Hz$ .

Explanation:

The frequency $f$ of a wave is the number of wavelengths that this wave covers in unit time (typically a second.)

The wave in this question travels at $v = 15\; \rm m \cdot s^{-1}$ . In other words, this wave covers $15\; \rm m$ in unit time (a second.) How many wavelengths $\lambda$ would that $15\; \rm m\;$ correspond to?

The question states that the wavelength of this wave is $\lambda = 5\; \rm m$ . Therefore, there would be $15 / 5 = 3$ wavelengths in the $15\; \rm m$ span that this wave covered in the unit time of one second ( $1\; \rm s$ .) Hence, the frequency of this wave would be $3\; \rm s^{-1}$ (three per second,) which is equivalent to $3\; \rm Hz$ (three Hertzs.)

In general, the frequency $f$ of a wave with speed $v$ and wavelength $\lambda$ would be:

$\displaystyle f = \frac{v}{\lambda}$ .

For the wave in this question:

$\begin{aligned}f &= \frac{v}{\lambda} \\ &= \frac{15\; \rm m \cdot s^{-1}}{3\; \rm s} = 3\; \rm s^{-1} = 3\; \rm Hz\end{aligned}$ .

3 0

3 years ago