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3 years ago

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The coordinates of the vertices of a right triangle are (0,0), (5,0) and (0,3) what statement is true

1 answer:

Tom [10]3 years ago

7 0

What grade level is this

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Which ordered pair is a solution of the system ?

drek231 [11]

Hello!

Since we already see an equation that equals y (-2x-4), we can plug that equation into the first to solve for x.

x+4(-2x-4)=19
x-8x-16=19
-7x=35
x=-5

Now that we know the value of x, we will plug it into the second equation to solve for y.

y=-2(-5)-4
y=10=4
y=6

This gives us the answer below

$\left \{ {{x=-5} \atop {y=6}} \right.$

The correct answer is A) (-5,6)

I hope this helps!

7 0

3 years ago

12.20h - 7.15 = 90.45

zhannawk [14.2K]

Answer:

H=8

Step-by-step explanation:

12.2H-7.15=90.45

12.2H=90.45+7.15

12.2H=97.6

H=8

6 0

3 years ago

Read 2 more answers

Pls help this homework is due tomorrow and I’m so confused thank you for taking your Time x

olchik [2.2K]

Answer:

a) x= 75

b) 105 is the same angle as angle B, I subtracted 180 by 105

180-105= 75

4 0

3 years ago

Sonji paid $25 for two scarves, which were different prices. When she got home she could not find the receipt. She remembered th

Oksanka [162]

Answer:

$14

Step-by-step explanation:

Make the variables:

x

x + 3

2x + 3 = 25

2x = 22

x = 11

11, 14

5 0

3 years ago

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I have the question in a screengrab. Thank you, whoever helps me.

nata0808 [166]

To simplify

$\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}$

we need to use the fact that

$\sqrt[4]{x^4}=|x|$

Why the absolute value? It's because $(-x)^4=(-1)^4x^4=x^4$ .

We start by rewriting as

$\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}$

$\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}$

Since $x\neq0$ , we have $\dfrac xx=1$ , and the above reduces to

$\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}$

Then we pull out any 4th powers under the radical, and simplify everything we can:

$\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}$

$\dfrac1{|2y|}\sqrt[4]{3x^2}$

where $y>0$ allows us to write $\dfrac yy=1$ , and this also means that $|y|=y$ . So we end up with

$\dfrac{\sqrt[4]{3x^2}}{2y}$

making the last option the correct answer.

7 0

3 years ago