Let the total mass of compound is 100g
The mass of each element will be
Al = 22.10 g
P = 25.40 g
O = 52.50 g
In order to determine the molecular formula we will calculate the molar ratio of the given elements
Atomic weight of Al : 27 g/ mol
Atomic weight of P : 3 1g /mol
Atomic weight of O : 16 g /mol
Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819
Moles of P = mass / atomic mass = 25.40/ 31 = 0.819
Moles of O = mass / atomic mass = 52.50/ 16 = 3.28
Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present
moles of Al = 0.819 / 0.819 = 1
moles of P = 0.819 / 0.819 = 1
moles of O = 3.28 / 0.819 = 4
So the empirical formula will be : AlPO4
Answer:
Subtract them.
Explanation:
''''"Since all number in scientific notation have base 10, we can always multiply them and divide them. To multiply two numbers in scientific notation, multiply their coefficients and add their exponents. To divide two numbers in scientific notation, divide their coefficients and subtract their exponents."""""
I was actually learned about this in school just found an source.
178.87 grams of sulphur dioxide is formed according to the equation given.
Explanation:
The balanced chemical reaction for the process is:
4 FeS2 + 11 O2 ⇒ 2Fe2O3(-) + 8 SO2
the reaction involving FeS and oxygen having balanced chemical equation as:
moles of oxygen given as 3.84
so when 11 moles of O2 reacts to form 8 moles SO2
3.84 moles of oxygen reacts to form x moles of SO2
= 
x = 
2.792 moles of sulphur dioxide will be formed
The mass can be calculated as number of moles x molar mass of 1 mole of SO2
= 2.792 x 64.066
= 178.87 grams of sulphur dioxide is formed.
Answer:
lower ionization should be the answer
Answer: 2 AgNO3(aq) + NiCl2(aq) ⇒ 2 AgCl(s) + Ni(NO3)2 (aq)
Explanation:
