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taurus [48]
3 years ago
6

How does the weight of your skin compare to the weight of your brain

Chemistry
1 answer:
yuradex [85]3 years ago
7 0
"Skin weighs twice as much as the brain"

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What is the National Suicide rate for Teens?
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I think it is 11% I read it on a article on msn.
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4 years ago
How to solve for enthalpy for changes​
Natasha_Volkova [10]
Always use this method !!! always

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4 years ago
Which statement describes a chemical property that can be used to distinguish between compound A and compound B?
AURORKA [14]

Answer:

Explanation:

(4) A does not burn in air, and B does burn in air is your answer. Flammability is a chemical property while the rest of these are physical properties.

Still stuck? Get 1-on-1 help from an expert tutor now.

7 0
3 years ago
A researcher dilutes 30.0 ml of ethanol to 300.0 ml with distilled water. what is the percentage concentration by volume of the
Len [333]

Answer: 9.09 %

Explanation:

To calculate the  percentage concentration by volume, we use the formula:

\text{Volume percent of solution}=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100

Volume of ethanol (solute) = 30 ml

Volume of water (solvent) = 300 ml

Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml

Putting values in above equation, we get:

\text{Volume percent of solution}=\frac{30}{30+300}\times 100=9.09\%

Hence, the volume percent of solution will be 9.09 %.

3 0
3 years ago
Read 2 more answers
Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equa
MA_775_DIABLO [31]

Answer:

m_{O_2}=61.87gO_2

m_{CO_2}=85.07gCO_2

Explanation:

Hello,

Considering the given reaction's stoichiometry, grams of oxygen result:

m_{O_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molO_2}{1molC_6H_{12}O_6}*\frac{32gO_2}{1molO_2}\\m_{O_2}=61.87gO_2

Moreover, the mass of produced carbon dioxide turns out:

m_{CO_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6}*\frac{44gCO_2}{1molCO_2}\\m_{O_2}=85.07gCO_2

Best regards.

6 0
3 years ago
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