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IgorLugansk [536]
3 years ago
6

Call me fortnite because boys play me 24/7 it's a joke!!!!!!

Chemistry
2 answers:
elena55 [62]3 years ago
4 0

Answer:

this was funny u made me happy rn that i was sad

Explanation:

guapka [62]3 years ago
4 0

Answer:

ur lost 0 pr dog water box like fish dont talk to me unless u get earnings stop talking get good no earnings ur lost 360 movement still cant help u play keyboard it helps get good kyle thats me freerer then everything ur freere then a walmart basket 1 2 chris brow u LIKE GET GOOD KID UR BAD HEAL PLEASE SO I CAN DO MORE DAMAGE AND CLIP U EVEN HARDER

Explanation:

no pls let me

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viva [34]
B.
I hope this will help a bit (Forgive me of its wrong pls)
7 0
3 years ago
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When oil and water are mixed vigorously, the oil is broken up into tiny droplets that are dispersed throughout the water. this d
Bumek [7]
Emulsion or heterogeneous mixture
4 0
2 years ago
In a certain experiment, 28.0 mL of 0.250 M HNO3and 53.0 mL of 0.320 M KOH are mixed. Calculate the number of moles of water for
Xelga [282]

Answer:

The number of moles of water formed in the resulting reaction is 6.03

[H+]: 37,2 M

[OH-]: 37,2 M

Explanation:

HNO3  +  KOH ----> KNO3 + H2O

First, we must discover the limiting reagent and we need to find out the moles, we use for this.

Moles that are used = Molarity / volume

HNO3 : 0,250 mol/L / 0,028L = 8,93 moles

KOH : 0,320 mol/L / 0,053L = 6,03 moles

The ratio of the reagents by stoichiometry is 1 to 1, so the limiting reagent is KOH, if I need 1 mole of nitric per mole of KOH, for every 8.93 moles I will need the same. However I have only 6.03 moles of KOH

The ratio of the reagents/products by stoichiometry is 1 to 1 so if I need 1 mol of KOH to make 1 mol of Water, 6,03 moles of KOH are used to make 6,03 moles of H2O.

The equilibrium of water is this:

2H2O ⇄ H3O+  +  OH-

2 moles of water are broken down into 1 mole of hydronium (H3O +) and 1 mole of hydroxyl (OH-)

6,03 moles of water are broken down into the half of those moles, so we have 3,015 moles of H3O+ and 3,015 moles of OH- but these moles are in 81,0 mL (the volume of the two solutions, 28 mL + 53 mL)

We must find out the moles in 1000 mL (1 L) so let's apply the rule of three.

81 mL ____ 3,015 moles

1000 mL ___ ( 1000 . 3,015) /81 = 37,2 M

7 0
2 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
Explain why, at room temperature, CO2 is a gas and CS2 is a liquid. You may use diagrams as part of your explanation.
eduard

Explanation:

A. Hydrogen bonding is present in CS2 but not in CO2.

B. CS2 has greater dipole moment than CO2 and thus the dipole-dipole forces in CS2 are stronger.

C. CS2 partly dissociates to form ions and CO2 does not. Therefore, ion-dipole interactions are present in CS2 but not in CO2.

D. The dispersion forces are greater in CS2 than in CO2.

<u><em>PLS MARK BRAINLIEST :D</em></u>

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2 years ago
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