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3 years ago

Someone please help me with this math problem! :(

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

The formula for this area is basexheight so you have to mutiply (2x+3)x(ax+5) and this multiplication must be equal to 8x^2+bx+15. If you do the multiply and then equalization you will get 2ax^2+10x+3ax+15 = 8x^2+bx+15.
Now is easy to see that 2ax^2 must be equal to 8x^2 so 2a=8 you solve for a and you get a=4. The same step for b you have 10x+3ax= bx so 10+3a=b as you know now a is 4 so 10+12=b you solve for b and you get b=22.
The answer is a=4 and b=22

Assoli18 [71]3 years ago

5 0

Area of a parallelogram=base x heigth
Data:
base=(2x+3)
heigth=(ax+5)
area of this parallelogram=8x²+bx+15

Therefore:
8x²+bx+15=(2x+3)(ax+5)
8x²+bx+15=2ax²+10x+3ax+15
8x²+bx+15=2ax²+(10+3a)x+15

Then:
8x²=2ax²
a=(8x²)/(2x²)=4

bx=(10+3(4))x
bx=(10+12)x
b=22x/x=22

Answer: a=4 and b=22.

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Identify the name and label the parts of the following polynomial: − 2x^4+24^2-10

lianna [129]

-2x^4 + 24x^2 - 10

u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2

a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4

how many constants can a polynomial have ? I am not sure about this one...I wanna say 1 because u can simplify it if it has more then 1...but I am not 100% sure on this one

3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5

when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms

7 0

3 years ago

baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago

Help I do not know how do you do this ?

aliya0001 [1]

$m\angle LKJ=360-m\angle KJM-m\angle JML-m\angle MLK\\
m\angle LKJ=360-132-48-m\angle MLK\\
m\angle LKJ=180-m\angle MLK\\\\
m\angle MLK=180-m\angle KLN\\
m\angle MLK=180-150\\
m\angle MLK=30^{\circ}\\\\
m\angle LKJ=180-30\\
\boxed{m\angle LKJ=150^{\circ}}$

6 0

3 years ago

Wich of the expressions simplify 10y + 8??

vovangra [49]

Answer:

2(5y+4)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

How do you write y=25x-56 in standard form?

Tcecarenko [31]

To put a slope-intercept into standard form, you have to first cancel out the fractions. So:
$y = \frac{2}{5}x - \frac{5}{6}$

Turns into:
$(5)(6)y = (\frac{2}{5}x - \frac{5}{6})(5)(6)$

Simplify:
$30y = (\frac{2}{5}x - \frac{5}{6})(30)$

Distribute:
$30y = 12x- 25$

Since you want to get x and y on the same side, you subtract 12x from both sides to get:
$-12x+30y = -25$

So, your answer is C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.

6 0

3 years ago