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crimeas [40]
3 years ago
11

A 4.5cm tall object is placed 28cm in front of a spherical mirror. It is to produce a virtual image that is upright and 3.5cm ta

ll.
a) What type of mirror is used ?
b) Where is the image located ?
c) What is the focal length ?
d) What is the radius of curvature ?
Physics
1 answer:
Ostrovityanka [42]3 years ago
7 0
A- convex B- 21.77cm C- 0.01022cm D- 0.02044cm
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Consider the f(x) = Acos(x) function shown in the figure in blue color. What is the value of amplitude A for this function?
Alex73 [517]

The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

<h3>What is amplitude of a wave?</h3>

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

<h3>Amplitude of the red colored wave</h3>

From the graph, the amplitude of the red colored wave is 1 unit.

<h3>Amplitude of the blue colored wave</h3>

From the graph, the amplitude of the red colored wave is 2.1 unit.

Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

Learn more about amplitude here: brainly.com/question/3613222

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3 0
2 years ago
In a crash test, a truck with mass 2100 kg traveling at 22 m/s smashes head-on into a concrete wall without rebounding. The fron
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Answer:

a) 11 m/s

b) 0.0564 s

Explanation:

Given:

m = 2100 kg

vi = 22 ..... m/s before collision

vf = 0 ......after collision to stop

Δs = 0.62   distance traveled after collision .. crumpling of truck

Part a

V_{avg} = \frac{vi- vf}{2}\\\\V_{avg} = \frac{22- 0}{2}\\\\ V_{avg} = 11 m/s

Part b

vf = vi + a*t\\vf^2 = vi^2 + 2*a*s\\\\0 = 22 + a*t\\t = -22 /a\\\\0 = 484 +2*a*(0.62)\\a = - 390.3232 m/s^2\\\\t = -22/(-390.3232)\\\\t = 0.0564 s

7 0
4 years ago
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For me: WASH OUR HANDS REGULARLY

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