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jeka57 [31]
2 years ago
7

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

Physics
1 answer:
ser-zykov [4K]2 years ago
5 0

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

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Skid Marx set the world record for acceleration as he went from zero to 10 m/s in 3 seconds. How far did he travel in that time?
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12000 miles per hour

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Three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously w
salantis [7]

Answer:

They will never meet.

Explanation:

Given that three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously with a constant speed vv, with the first shark heading constantly toward the second, the second toward the third, and the third toward the first. How soon will the sharks converge at one point ?

Since the three sharks are located at the vertices of an equilateral triangle whose side equals, and the first shark is moving toward the second, the second is moving toward the third, and the third shark is moving toward the first, the movement of the three shark will form a circular motion.

Since the three sharks are moving at a constant speed, the three sharks will never meet because the distances between them are also the same.

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6 0
2 years ago
Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay
Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
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