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2 years ago

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

Physics

1 answer:

ser-zykov [4K]2 years ago

5 0

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

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Two boys are standing on a bridge 10 m above a stream. One boy throws a rock horizontally with speed of 5.0 m/s at exactly the s

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C) Both rocks strike the water at the same time.

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3 years ago

Truck drivers approaching a steep hill that they must climb often increase their speed. What good does this do, if any?

Inga [223]

Um, this doesn't make any sense. By climbing a hill, you are decreasing your momentum and kinetic energy, so it slows you down. The only positive, is after you have climbed the hill, you have more potential energy, and it will be released once you go down the hill, but you will not be as fast as if you ignored the hill.

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2 years ago

Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is hi

Solnce55 [7]

Answer:

The weight at a distance 2 RE from surface of earth is W/9

Explanation:

For the value of acceleration due to gravity (g), we have a formula, that is:

g = (G)(ME)/(RE)² ----- equation (1)

where,

G = Gravitational Constant

ME = Mass of Earth

RE = Radius of Earth

g = Acceleration due to gravity on surface of earth = 9.8 ms²

When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.

Therefore, equation (1) becomes:

gh = (G)(ME)/(3RE)²

where,

gh = acceleration due to gravity at height

gh = (G)(ME)/(RE)²9

using equation (1), we get:

gh = g/9

Now, he weight is given by formula:

W = mg ------- equation (2)

At height 2RE

Wh = (m)(gh)

where,

Wh = Weight at height = ?

m = mass of astronaut

Therefore, using vale of gh, we get:

Wh = mg/9

Using equation (2), we get:

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3 years ago

So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would tha

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Answer:

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Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system

The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;

$Efficiency \, \% = \dfrac{AMA}{IMA} \times 100$

Explanation:

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3 years ago

(ii) Describe how the acceleration of the train at time t = 100 s differs from the acceleration

quester [9]

Explanation:

Acceleration is the rate of change of velocity with time. When acceleration increases a body moves a faster velocity.

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3 years ago