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jeka57 [31]
2 years ago
7

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

Physics
1 answer:
ser-zykov [4K]2 years ago
5 0

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

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If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
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Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

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At 10m, the total amount of energy is equivalent to:

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To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

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