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3 years ago

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

Physics

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

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a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet

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Answer:

Explanation:

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3 years ago

Which formula represents final velocity of an object with average acceleration?

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2 years ago

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Explanation:

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$\boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }}$

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Given that

u = 8m/ s
$\theta$ = 40°

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$= \frac{64 \times \sin(80) }{10}$

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Hence,

$\mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } }$

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