Answer:
Correct option is
A
450 V and 15 A
P
in
=I
p
V
p
⇒T
p
=
V
p
P
in
=
200N
3000W
=15A
Efficciencyofthetransformer
η=
P
in
P
out
=
V
p
I
p
V
s
I
s
⇒
100
90
=
3000
6V
s
V
s
=
100×6
90×5000
=450V
Hence,
option (A) is correct answer.
Power = energy/time=20/4=5.0
Answer:
98 joules
Explanation:
1/2 of 28 = 14
14 multiply by 7= 98 joules
Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:

You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:

hence, the speed of the Hubble is approximately 384km/min