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Archy [21]
3 years ago
12

Describe Newton's law of gravitation and its application?​

Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

Newton's law of gravitation states that every object in this universe attracts every other object with a force called gravity,

when the distance between the two object is increased the gravitational force decreases by its square,

and when the mass an object increases the gravitational force also increases,

therefore, gravitational force is directly proportional to the mass of the two objects and is square inversely proportional to distance between them.

Hope it helped u,

pls mark as the brainliest and put thanks

^_^

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True or False: When looking at kinetic vs. thermodynamic products the kinetic product predominates at low temperature.
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Answer:

true answer this question

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3 years ago
The condition required to work to be done​
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Answer:

work=f(costheta)

Explanation:

work is done when a force acts on a body and displaces it on the direction of force

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Hai điện tích +q và -q (q>0) đặt tại hai điểm a và b với AB=a, M là một điểm nằm trên đường trung trực của AB cách AB một đoạ
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3 years ago
A 15-ft3 tank contains oxygen initially at 14.7 psia and 80°F. A paddle wheel within the tank is rotated until the pressure insi
Nikolay [14]

Explanation:

Equation for energy balance will be as follows.

         \Delta E_{system} = E_{in} - E_{out}

        \Delta U = W_{in} - Q_{out}

Hence,    W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

Therefore, we will calculate the final temperature as follows.

            \frac{P_{1}V}{T_{1}} = \frac{P_{2}V}{T_{2}}

       T_{2} = \frac{20 psia}{14.7}(638 R)

                   = 868.03 R

Now, we will calculate the mass as follows.

             m = \frac{P_{1}V}{RT_{1}}

                 = \frac{14.7 psia \times 15 ft^{3}}{0.3353 psi ft^{3}/lbm R \times 638 R}

                 = 1.031 lbm

Hence,

        W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

Putting the values into the above equation as follows.

            W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

    W_{in} = 20 Btu + 1.031 lbm (\frac{0.160 Btu}{lbm R})(735 - 540)R

            W_{in} = 655.2 Btu

Thus, we can conclude that work done by paddle wheel is 655.2 Btu.

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3 years ago
Where is potential energy the greatest on a rollercoaster?
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On a roller coaster, the greatest potential energy is at the highest point of the roller coaster
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