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Archy [21]
3 years ago
12

Describe Newton's law of gravitation and its application?​

Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

Newton's law of gravitation states that every object in this universe attracts every other object with a force called gravity,

when the distance between the two object is increased the gravitational force decreases by its square,

and when the mass an object increases the gravitational force also increases,

therefore, gravitational force is directly proportional to the mass of the two objects and is square inversely proportional to distance between them.

Hope it helped u,

pls mark as the brainliest and put thanks

^_^

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If you were asked to describe metals and magnetism you could say?
Anettt [7]
Some metals having unpaired electrons contain a strong magnetic response, i.e, they can be magnetized by an external magnetic field.
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3 years ago
The Trans-Siberian Railroad is the longest single railroad in the world. Starting in Moscow, the tracks stretch 9,354 km across
Lubov Fominskaja [6]
103.9 hours, if you never stopped for any reason.
4 0
3 years ago
(a) How many fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit
Ainat [17]

Answer:

a

The number of fringe is  z  = 3 fringes

b

The  ratio is I = 0.2545I_o

Explanation:

a

 From the question we are told that

        The wavelength is  \lambda = 600 nm

        The distance between the slit is  d = 0.117mm = 0.117 *10^{-3} m

        The width of the slit is  a = 35.7 \mu m = 35.7 *10^{-6}m

let  z be the number of fringes that appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern is  and this mathematically represented as

             z = \frac{d}{a}

Substituting values

             z = \frac{0.117*10^{-3}}{35.7 *10^{-6}}  

             z  = 3 fringes

b

   From the question  we are told that the order  of the bright fringe is  n = 3

   Generally the intensity of  a pattern  is mathematically represented as

                 I = I_o cos^2 [\frac{\pi d sin \theta}{\lambda} ][\frac{sin (\pi a sin \frac{\theta}{\lambda } )}{\pi a sin \frac{\theta}{\lambda} } ]

Where I_o is the intensity  of the  central fringe

 And  Generally  sin \theta = \frac{n \lambda }{d}

               I = I_o co^2 [ \frac{\pi (\frac{n \lambda}{d} )}{\lambda} ] [\frac{\frac{sin (\pi a (\frac{n \lambda}{d} ))}{\lambda} }{\frac{\pi a (\frac{n \lambda}{d} )}{\lambda} } ]

               I = I_o cos^2 (n \pi)[\frac{\frac{sin(\pi a (\frac{n \lambda}{d} ))}{\lambda} )}{ \frac{ \pi a (\frac{n \lambda }{d} )}{\lambda} } ]

               I = I_o cos^2 (3 \pi) [\frac{sin (\frac{3 \pi }{6} )}{\frac{3 \pi}{6} } ]

                I = I_o (1)(0.2545)

                  I = 0.2545I_o

6 0
3 years ago
The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti
Ksenya-84 [330]

Answer: The answer is B

Explanation: It is staying in a steady speed position

5 0
2 years ago
Read 2 more answers
How many electrons does it take to make up 4.33 C of charge?
Dovator [93]

Answer:

Number of electrons, n=2.7\times 10^{19}

Explanation:

It is given that,

Charge, q = 4.33 C

We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :

q=ne

n = number of electrons

e = electron's charge

n=\dfrac{q}{e}

n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}

n=2.7\times 10^{19}

So, the number of electrons are 2.7\times 10^{19} Hence, this is the required solution.  

7 0
2 years ago
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