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3 years ago

13

Determine the magnitude of the acceleration for the speeding up phase.

1 answer:

Arisa [49]3 years ago

8 0

Determine the magnitude of the acceleration for the speeding up phase<span>. Express your answer to two significant figures and include the appropriate units. I've tried 2.8 m/s^2, and 1.1 m/s^2, but they are both wrong. </span>Determine the magnitude of the acceleration<span> for the slowing down </span>phase<span>.</span>

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Give an example of a Claim.

Olin [163]

Answer:

Yeah

Explanation:

Look at the pic!!

5 0

3 years ago

One average force has a magnitude that is three times as large as that of

valentinak56 [21]

The time interval in which the larger force act is 1.1 seconds.

<h3>What is impulse?</h3>

The impulse produced by an object is determined from the product of force and time of force of the object.

The impulse experienced by an object is the product of mass and velocity of the object or simply the impulse experienced by object is equal to change in the momentum of an object.

J = Ft

where;

F is the applied force
t is the time of force acting

The magnitude of the force that produce impulse of 3 Ns for 3.2 seconds is calculated as;

F = J/t

F = (3 Ns) / (3.2 s)

F = 0.94 N

The magnitude of the force that is three times larger is calculated as;

F₂ = 3 x 0.94 N

F₂ = 2.82 N

The time interval of the larger force is calculated as;

t₂ = J/F₂

t₂ = 3 / 2.82

t₂ = 1.1 seconds

Thus, the impulse experienced by an object is a function of force and time of force action.

Learn more about impulse here: brainly.com/question/25700778

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5 0

1 year ago

(a) Are the radiating electric field lines around a charged particle straight lines when the particle is stationary?

s2008m [1.1K]

Answer:

Yes

Explanation:

(a)

Yes, the radiating electric field lines around a stationary charged particle are straight lines when the particle is stationary.

7 0

4 years ago

During take-off a 8kg model rocket is burning fuel causing its speed to increase

77julia77 [94]

The strength of the thrust is 122 newtons.

The motion of the rocket is described by the second Newton's law, whose model is shown below:

$\Sigma F = F - D = m\cdot a$ (1)

Where:

$F$ - Thrust, in newtons
$D$ - Drag, in newtons
$m$ - Mass of the rocket, in kilograms
$a$ - Net acceleration of the rocket, in meters per square second

If we know that $D = 90\,N$ , $m = 8\,kg$ and $a = 4\,\frac{m}{s^{2}}$ , then the strength of the thrust is:

$F = D + m\cdot a$

$F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)$

$F = 122\,N$

The strength of the thrust is 122 newtons.

To learn more on Newton's laws, we kindly invite to check this verified question: brainly.com/question/13678295

4 0

3 years ago

Two sinusoidal waves are moving through a medium in the positive x-direction, both having amplitudes of 7.00 cm, a wave number o

lys-0071 [83]

Answer:

0.99 m

Explanation:

Parameters given:

Amplitude, A = 7.00cm

Wave number, k = 3.00m^-1

Angular Frequency, ω = 2.50Hz

Period = 6.00 s

Phase, ϕ = π/12 rad

Note: All parameters are the same for both waves except the phase.

Wave 1 has a wave function:

y1(x, t) = Asin(kx - ωt)

y1(x, t) = 7sin(3x - 2.5t)

Wave 2 has a wave function:

y2(x, t) = Asin(kx - ωt + ϕ)

y2(x, t) = 7sin(3x - 2.5t + π/12)

π is in radians.

When Superposition occurs, the new wave is represented by:

y(x, t) = 7sin(3x - 2.5t) + 7sin(3x - 2.5t + π/12)

y(x, t) = 7[sin(3x - 2.5t) + sin(3x - 2.5t + π/12)]

Using trigonometric function:

sin(a) + sin(b) = 2cos[(a - b)/2]sin[(a + b)/2]

Where a = 3x - 2.5t, b = 3x - 2.5t + π/12

We have that:

y(x, t) = (2*7)[cos(π/24)sin(3x - 2.5t + π/24)]

Therefore, when x = 0.53cm and t = 2s,

y(x, t) = (2*7)[cos(π/24)sin{(3*0.53) - (2.5*2)+ π/24}]

y(x, t) = 14 * 0.9914 * 0.0713

y(x, t) = 0.99 m

The height of the resultant wave is 0.99cm

5 0

3 years ago