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2 years ago

During take-off a 8kg model rocket is burning fuel causing its speed to increase

Physics

1 answer:

77julia77 [94]2 years ago

4 0

The strength of the thrust is 122 newtons.

The motion of the rocket is described by the second Newton's law, whose model is shown below:

$\Sigma F = F - D = m\cdot a$ (1)

Where:

$F$ - Thrust, in newtons
$D$ - Drag, in newtons
$m$ - Mass of the rocket, in kilograms
$a$ - Net acceleration of the rocket, in meters per square second

If we know that $D = 90\,N$ , $m = 8\,kg$ and $a = 4\,\frac{m}{s^{2}}$ , then the strength of the thrust is:

$F = D + m\cdot a$

$F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)$

$F = 122\,N$

The strength of the thrust is 122 newtons.

To learn more on Newton's laws, we kindly invite to check this verified question: brainly.com/question/13678295

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A coil with 55 loops has its flux change from 0 Wb to 0.0266 Wb in a certain amount of time, generating 5.22 V of EMF. How much

Eduardwww [97]

Answer:

0.280 s

Explanation:

I set it up as 5.22=(55)(0.0266)/x and then solved for x to be 2.80.

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2 years ago

Briefly explain how einstein's special theory of relativity explains the perpendicular (right hand screw like) behavior of movin

ddd [48]

Einstein's special theory of relativity explains that the electric and magnetic fields are both can formulate together in mathematically.

It is given Einstein's special theory of relativity.

It is find the Einstein's special theory of relativity explains the perpendicular behavior of moving charges without recourse to invoking the concept of a magnetic field.

<h2>What is Einstein's special theory of relativity?</h2>

As we know that one charge creates a field and its that field that actually exerts a force on the other charge. Here we it gives the relationship of two fields like electric field and magnetic field and gives the formula for electromagnetic objects.

Special relativity fixes the problem by the points that the magnetic force in one frame of reference easily be an electric force in other and also some of the combination of them in a frame.

Thus, Einstein's special theory of relativity explains that the electric and magnetic fields are both can formulae together in mathematically.

Learn more about magnetic field here:

brainly.com/question/23096032

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3 0

1 year ago

Please answer. Thanks

Brilliant_brown [7]

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8 0

2 years ago

8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (

love history [14]

(1) acceleration, a = 4 m/ $s^{2}$ (2) acceleration of 10 N, $a_{1}$ = 1 m/ $s^{2}$ and acceleration of 30 N, $a_{2}$ = 3 m/ $s^{2}$

Explanation:

Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
Let $a_{1}$ be the acceleration for force 10 N, to find acceleration rearrange the equation to a = $\frac{F}{m}$ . When we substitute 10 N force and 10 kg mass of the box in the equation. We will get $a_{1}$ = 1 m/ $s^{2}$

Let $a_{2}$ be the acceleration for force 30 N, to find acceleration rearrange the equation to F = $\frac{F}{m}$ . When we substitute 30 N force and 10 kg mass of the box in the equation. We will get $a_{2}$ = 3 m/ $s^{2}$
To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/ $s^{2}$

3 0

2 years ago

A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0

2 years ago