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OverLord2011 [107]
3 years ago
14

During take-off a 8kg model rocket is burning fuel causing its speed to increase

Physics
1 answer:
77julia77 [94]3 years ago
4 0

The strength of the thrust is 122 newtons.

The motion of the rocket is described by the second Newton's law, whose model is shown below:

\Sigma F = F - D = m\cdot a (1)

Where:

  • F - Thrust, in newtons
  • D - Drag, in newtons
  • m - Mass of the rocket, in kilograms
  • a - Net acceleration of the rocket, in meters per square second

If we know that D = 90\,N, m = 8\,kg and a = 4\,\frac{m}{s^{2}}, then the strength of the thrust is:

F = D + m\cdot a

F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)

F = 122\,N

The strength of the thrust is 122 newtons.

To learn more on Newton's laws, we kindly invite to check this verified question: brainly.com/question/13678295

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vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
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<span>And now, we can use a velocity formula to find the distance traveled: </span>
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<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
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