Question

Which combination of three concurrent forces acting on a body could not produce equilibrium?

Answer 1

All the three concurrent forces acting on a body will not produce equilibrium.

The given parameters:

1. 1 N, 3 N and 5 N

2. 2N, 2N and 2 N

3. 3N, 4N and 5 N

4. 4N, 4N and 5 N

Concurrent forces lie on the same plane and their line of action pass through a common point.

A body under concurrent forces is in equilibrium if the resultant of the forces on the body is zero.

$\Sigma F = 0\\\\F_1 + F_2 + F_3 = 0\\\\F_1 + F_ 2 = - F_3$

where;

$F_3$ is the equilibrant force

First set of concurrent forces;

$1 \ N \ + \ 3\ N = 4 \ N\\\\F_ 3 = 5 \ N\\\\5 \ N > 4 \ N$

Second set of concurrent forces;

$2 \ N \ + \ 2 \ N = 4 \ N\\\\F_ 3 = 2 \ N\\\\4 \ N > 2 \ N$

Third set of concurrent forces;

$3 \ N \ + \ 4 \ N = 7 \ N\\\\F_ 3 = 5 \ N\\\\7 \ N > 5 \ N$

Fourth set of concurrent forces;

$4 \ N \ + \ 4 \ N = 8 \ N\\\\F_ 3 = 5 \ N\\\\8 \ N > 5 \ N$

Thus, we can conclude that all the three concurrent forces acting on a body will not produce equilibrium.

Learn more about concurrent forces here: brainly.com/question/20165540