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2 years ago

Which combination of three concurrent forces acting on a body could not produce equilibrium?

Physics

1 answer:

mixer [17]2 years ago

3 0

All the three concurrent forces acting on a body will not produce equilibrium.

The given parameters:

Concurrent forces lie on the same plane and their line of action pass through a common point.

A body under concurrent forces is in equilibrium if the resultant of the forces on the body is zero.

$\Sigma F = 0\\\\F_1 + F_2 + F_3 = 0\\\\F_1 + F_ 2 = - F_3$

where;

$F_3$ is the equilibrant force

First set of concurrent forces;

$1 \ N \ + \ 3\ N = 4 \ N\\\\F_ 3 = 5 \ N\\\\5 \ N > 4 \ N$

Second set of concurrent forces;

$2 \ N \ + \ 2 \ N = 4 \ N\\\\F_ 3 = 2 \ N\\\\4 \ N > 2 \ N$

Third set of concurrent forces;

$3 \ N \ + \ 4 \ N = 7 \ N\\\\F_ 3 = 5 \ N\\\\7 \ N > 5 \ N$

Fourth set of concurrent forces;

$4 \ N \ + \ 4 \ N = 8 \ N\\\\F_ 3 = 5 \ N\\\\8 \ N > 5 \ N$

Thus, we can conclude that all the three concurrent forces acting on a body will not produce equilibrium.

Learn more about concurrent forces here: brainly.com/question/20165540

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Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

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(A)

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From the formula of cylindrical capacitor,

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But we need capacitance per unit length so,

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$Q = C \Delta V$

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