Answer
Give that,
mass of two student m = 3.10 kg
distance from the axis of the rotation is r = 1 m
angular speed ω = 0.754 rad /s
moment of inertia I = 3.10 kg m²
position from the rotation of the axis is r_1 = 0.29 m
Total moment of inertia I ' = I + 2 m r²
= 3.1 +2 x 3.1 x( 1)^2
= 9.3 kg m²
moment of inertia inward horizontally from the position of rotation axis is
I" = I + 2 m r^2
= 3.1 + 2 * 3.1 kg ( 0.29)^2
= 3.62 kg m^2
a ) new angular speed is ω_1 =
=
= 1.94 rad /s
b ) K.E before the system pulls weight inward is
c )K.E after the system pulls weight inward is
Answer: so when a turbine converts the K.E and the potential of any moving fluid (more likely liquid or gas) to energy. once the proc is started the turbine generato, the fluid such as water, steam, combus gasses, or air pushes s big series of blades that have mounted on a shaft, which then will rotate the shaft that’s conn to the generator
Explanation: hope this helped plz mark brainest
Answer:
3.3×10⁻⁹ kg/s
Explanation:
There are two forces on the particle: weight force pulling down and drag force pushing up. At terminal velocity, the speed is constant, so the acceleration is zero.
∑F = ma
bv − mg = 0
b = mg / v
b = (10⁻¹³ kg) (9.8 m/s²) / (3×10⁻⁴ m/s)
b = 3.3×10⁻⁹ kg/s
Answer:
Ф = 142.674 degree
Ф = 2.490131057 rad
wavelength = 0.396316 λ
Explanation:
Given data
combined wave having an amplitude 0.64 times
to find out
answer in degrees, radians, and fraction of the wavelength
solution
let us consider these two wave equation
Asin(ωt) and the Asin (ωt + Ф)
and here Ф is phase difference
so we say
resultant wave is
Y = Asin(ωt) + Asin (ωt + Ф) = Asin(ωt + Ф/2) cos ( Ф/2)
so Y = A' sin(ωt + Ф/2)
we know that here resultant wave amplitude is 2A cos ( Ф/2)
so
put A= 0.64 A
so 2Acos ( Ф/2) = 0.64 A
and Ф/2 = 71.3370
Ф = 142.674 degree
Ф = 2.490131057 rad
so wavelength is 2.490131057 / 2π
wavelength = 0.396316 λ