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pav-90 [236]
3 years ago
15

A pitcher throws a baseball horizontally from the mound to home plate. The ball falls 0.913 m (2.99 ft) by the time it reaches h

ome plate 18.3 m (60 ft) away. How fast was the pitcher's pitch?
Physics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

42.42 m/s

Explanation:

Let g = 9.81 m/s2. The time it takes for the ball to fall vertically 0.913m

s = gt^2/2

t^2 = 2s/g = 2*0.913/9.81 = 0.186

t = \sqrt{0.186} = 0.431 s

This is also the time it takes for the ball to travel horizontally 18.3 m across. So the ball horizontal velocity is

18.3 / 0.431 = 42.42 m/s

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