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3 years ago

12

Explain why a description of motion has to be in reference to something else. ( I don't know if this is physics, it's science )

THANKS FOR THE HELP!!!!!

1 answer:

timurjin [86]3 years ago

8 0

Description of motion has to refer to the change in distance over a certain amount of time, or balanced forces

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Which of the following is NOT a physical mechanism that causes air to rise?A) orographic liftingB) frontal wedging C) adiabatic

liq [111]

Answer:

Option C

Explanation:

Adiabatic cooling systems function similarly to dry cooling systems, but with the incorporation of pre-cooling pads; running water over pre-cooling pads and drawing air through the pads depresses the ambient dry bulb of the incoming air. The depressed dry bulb allows for greater system heat rejection.

he result of this is that adiabatic systems are highly effective in hot, dry environments, while using less water than traditional evaporative units. Adiabatic units also deliver the required cooling capacity in a smaller footprint and/or lower fan motor horsepower than a completely dry cooler/condenser.

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3 years ago

Near the surface of Earth, an electric field points radially downward and has a magnitude of approximately 100 N/C. 1) What char

scoundrel [369]

Answer:

$-2.50\times10^{-4} \text{ C}$ or -0.000250 C

Explanation:

The field points downward, which is the direction of a positive charge. In order for the penny to rise, it has to have a negative charge since its direction is opposite that of the field.

To calculate the magnitude of the charge:

The penny is to accelerate upward so it must overcome gravity. Hence, the net force to cause it to accelerate it upward is the difference between the electrostatic force and its weight.

$F_N = F_E - W$

$F_E = F_N + W$

$F_E = ma + mg$

$F_E = m(a + g)$

$F_E = 0.0025(0.19+9.8)$

$F_E = 0.0025\times9.99$

Now, the electric field intensity is given by

$F_E = E \times q$

where q = charge

$q=\dfrac{F_E}{E}$

$q=\dfrac{0.0025\times9.99}{100}=0.00024975= 0.000250$ to 3 significant figures.

In standard form, q = $-2.50\times10^{-4} \text{ C}$ The negative sign indicates it has a negative charge, as explained initially.

5 0

3 years ago

How does the momentum of a fast object compare to that of a slow object if they both have the same mass?

Varvara68 [4.7K]

The momentum of a fast object compared to that of a slow object even if they both have the same mass, is their velocities.

Having same mass but different velocities results in different momentum.

Example: mass = 10kg
Velocity 1 = 50 Velocity 2 = 100
Momentum 1 = 10×50 = 500 Ns
Momentum 2 = 10×100 = 1000 Ns

Hope it helped!

3 0

3 years ago

An electric circuit has a 200 22 resistor and a current of 5 A. What is its voltage?

Wittaler [7]

Answer:

ccccccc. ccccccc ccc ccccccc c

8 0

3 years ago

A mass m at the end of a spring vibrates with a frequency

Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

$F = -kx$

And Newton's Second Law also states that

$F = ma = m\frac{d^2x}{dt^2}$

Combining two equations yields

$a = -\frac{k}{m}x$

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

$\omega = \sqrt{\frac{k}{m}}$

And given that ω = 2πf

the relation between frequency and mass becomes

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$ .

Let's apply this to the variables in the question.

$0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg$

6 0

3 years ago