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Anastaziya [24]
3 years ago
6

If a converging lens forms a real, inverted image 24.0 cm to the right of the lens when the object is placed 48.0 cm to the left

of a lens, determine the focal length of the lens
Physics
2 answers:
garri49 [273]3 years ago
5 0

Answer:

f = 16 cm

Explanation:

If a converging lens forms a real, inverted image 24.0 cm to the right of the lens when the object is placed 48.0 cm to the left of a lens, the focal length of the lens is 16 cm.

viva [34]3 years ago
4 0

Answer:

Focal length, f = 16 cm

Explanation:

Image distance, v = 24 cm

Object distance, u = -48 cm

We need to find the focal length of the lens. It can be determined using the lens formula as :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{24\ cm}-\dfrac{1}{(-48\ cm)}=\dfrac{1}{f}

f = 16 cm

So, the focal length of the converging lens is 16 cm. Hence, this is the required solution.

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Explanation:  

10 /9 Ω

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2 years ago
Scientific models have two basic types. Please select the best answer from the choices provided T F
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Scientific models have two basic types. FALSE.

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3 0
3 years ago
Four seconds after being launched, what is the height of a ball that starts from a height of 12 m with an initial upward velocit
MrMuchimi

Answer:

15.24 m/s in the downward direction

Explanation:

Given that the initial upward velocity of the ball is 24 m/s.

Assuming that the upward direction is positive.

As gravitational force acts in the downward direction and the direction of acceleration is the same as the direction of force, so the acceleration due to gravity will be negative.

Now, from the equation of motion, when an object is launched with initial velocity u, the final velocity, v, of an object after time t is v=u+at.

Given that u=24 m/s, t=4 seconds, g=-9.81 m/s^2.

So, the final velocity is

v= 24 + (-9.81)\times 4 \\\\\Rightarrow v= 24-9.81\times 4

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Here, the negative sign means the final velocity is in the downward direction.

Hence, the velocity after 4 seconds is 15.24 m/s in the downward direction.

8 0
3 years ago
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
White raven [17]

Answer:

400ft.    32ft/s       -32ft/s

Explanation:

In reality the gravitational acceleration is 9.81 so the quadratic coefficient of the function should be 9.81/2

Anyway for the sake of assumtion let us takes=160t-16t^2

 

ds/dt=160-32t=0

 

t=160/32= 5 seconds.

s=160*160/32-16*(160/32)^2= 400 mts

 

 

s=384 mts

160t-16t^2=384

i.e

16t^2-160t+384=0

 

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(t-6)(t-4)=0

t=[4,6]

we have to take t=4 because it is all the up i.e <5

 

velocity =v=ds/dt=160-32t

 

v=160-32*4=32 ft/sec still going up

 

for all the way down take t=6 whuch is >5

 

v=160-6*32=-32 ft/sec (falling down!!!)

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which force will decrease if the surface of a ramp is made smoother. gravity, magnetism, friction, or electricity
Leno4ka [110]
Friction will decrease
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3 years ago
Read 2 more answers
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